All categories

3 years ago

Draw a model to show 5.5/5

Mathematics

1 answer:

REY [17]3 years ago

7 0

I don't understand the question you are asking sorry.

You might be interested in

If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable

kkurt [141]

Answer:

The answer is " $\frac{26}{7}$ "

Step-by-step explanation:

The whole question can be found in the file attached.

$\to x + \frac{5}{7} = \frac{31}{7}\\\\$

Subtracting the $\frac{5}{7}$ from both sides of the equations:

$\to x +\frac{5}{7} - \frac{5}{7} = \frac{31}{7} - \frac{5}{7} \\\\$

$= \frac{31-5}{7} \\\\= \frac{26}{7} \\\\$

5 0

3 years ago

Integrate G(x,y,z)equalsz over the parabolic cylinder yequalszsquared, 0less than or equalsxless than or equals2, 0less than

yKpoI14uk [10]

I gather you're supposed to compute the integral of $G(x,y,z)=z$ over a surface $S$ that is the part of the parabolic cylinder $y=z^2$ with $0\le x\le2$ and $0\le z\le\frac{\sqrt{15}}2$ .

We can parameterize $S$ by

$\vec s(x,z)=x\,\vec\imath+z^2\,\vec\jmath+z\,\vec k$

with the given constraints on $x$ and $z$ . Take the normal vector to $S$ to be

$\vec s_x\times\vec s_z=-\vec\jmath+2z\,\vec k$

so that the surface element is

$\mathrm dS=\|\vec s_x\times\vec s_z\|\,\mathrm dx\,\mathrm dz=\sqrt{1+4z^2}\,\mathrm dx\,\mathrm dz$

Then in the integral, we have

$\displaystyle\iint_Sz\,\mathrm dS=\int_0^2\int_0^{\sqrt{15}/2}z\sqrt{1+4z^2}\,\mathrm dz\,\mathrm dx=\boxed{\frac{21}2}$

5 0

3 years ago

An equation that passes through (0, -2/3) and (-3, -2/3)

9966 [12]

Answer:

y = 0x - 2/3

Step-by-step explanation:

We are asked to find the equation of the line

Step1: find the slope

( 0 , -2/3) ( 3 , -2/3)

m = (y_2 - y_1 )/ (x_2 - x_1)

x_1 = 0

y_1 = -2/3

x_2 = 3

y_2 = -2/3

Insert the values into the equation

m =( -2/3 - (-2/3) / (3 - 0)

= -2/3 + 2/3 / 3

= 0 / 3

m = 0

Step 2: sub m into the equation

y = mx + c

y = 0x + c

Step 3: sub any of the two points given into the eqn

y = 0x + c

Let's pick ( 3 , -2/3)

x = 3

y = -2/3

-2/3 = 0(3) + c

-2/3 = 0 + c

c = -2/3

Step4: sub c into the equation

y = mx + c

y = 0x + c

y = 0x - 2/3

Therefore, the equation of the line is

y = 0x - 2/3

8 0

3 years ago

Identify the glide reflection rule in the given figure

Maslowich

Answer:

Option (3)

Step-by-step explanation:

Glide reflection of a figure is defined by the translation and reflection across a line.

To understand the glide rule in the figure attached we will take a point A.

Coordinates of the points A and A' are (2, -1) and (-2, 4).

Translation of pint A by 5 units upwards,

Rule to be followed,

A(x, y) → A"[x, (y + 5)]

A(2, -1) → A"(2, 4)

Followed by the reflection across y-axis,

Rule to be followed,

A"(x, y) → A'(-x, y)

A"(2, 4) → A'(-2, 4)

Therefore, by combining these rules in this glide reflections of point A we get the coordinates of the point point A'.

Option (3) will be the answer.

4 0

3 years ago

Can someone help me solve for x?

KatRina [158]

9x+72 = 4x+112
5x = 40
x = 8

3 0

3 years ago

Read 2 more answers