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hodyreva [135]
2 years ago
15

Determine whether the triangles can be proved similar. If they are similar, write a similarity statement. If they are not simila

r, explain why.

Mathematics
2 answers:
yuradex [85]2 years ago
4 0

Answer:

They are similar.  Triangle abc is similar to triangle edc.

Step-by-step explanation:

To prove that triangles are similar, you must show that the 3 angles in one triangle are equal to the 3 angles in the other triangle.  We know that they both have a 50 degree angle.  We can also see that they both have a right angle.  That means that the 3rd angle must also equal 40 (180-90-50).  So by AAA the two triangles are congruent.

Triangle ABC is similar to triangle EDC.

topjm [15]2 years ago
3 0

Answer:

triangle ABC is similar to triangle DCE

Step-by-step explanation:

Reason being that angles in triangle ABC Correspond to That of triangle DCE Eg triangle ABC=CDE

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HELP!
konstantin123 [22]

Answer:

1.  10 square yards

2.  $9.10

3.  36 girls

4.  20 cherries

5.  159 bracelets

Step-by-step explanation:

1.

The area of this figure would be the area of the SQUARE minus the area of the RECTANGLE (taken out).

The middle part is taken out (this is a rectangle).

View this as a square with sides 4 by 4 with a rectangle portion taken out. So the area can be said as:

Area = Area of Whole Square - Area of Middle Rectangle Taken Out

Lets calculate:

Area of Whole Square:

side * side = 4 * 4 = 16

Now,

Area of Middle Rectangle Taken Out:

Length * Width

The length is given as 3

The width would be 4 - two 1 from two sides, that is 4 - 1 - 1 = 2

So, area = 3 * 2 = 6

Area of figure = 16 - 6 = 10 square yards

2.

We have to find 20% of the bill.

The bill was 45.50 and we have to find 20% of 45.50.

We first convert percentage to decimal by dividing by 100:

20% = 20/100 = 0.20

Now we multiply this decimal with the bill to get our desired answer:

0.20 * 45.50 = $9.10

The tip is $9.10

3.

The ratio of boys (b) to girls (g) would be 2 is to 3.

There are 24 boys.

We can set up a ratio (fraction) with boys on top and girls on bottom.

Then we equate it with actual number of boys and girls (let it be g). So the ratio set-up would be:

\frac{2}{3}=\frac{24}{g}

To solve for g, the number of girls, we have to cross multiply and use algebra to solve. The process is shown below:

\frac{2}{3}=\frac{24}{g}\\2*g = 24*3\\2g=72\\g=\frac{72}{2}\\g=36

There are 36 girls in sixth grade

4.

For every "9" lemon, there are "4" cherries.

There are 45 lemons

If we think of "9" lemons as a "box", how many boxes of lemons are there?

45/9 = 5

Similarly, there would be "5" boxes of cherries. But there are "4" cherries per box. So there are:

4 * 5 = 20 cherries

We can also set up a ratio of cherry to lemon as 4 is to 9 and equate it with actual cherries (let it be "c") and lemons (45). Cross multiply and use algebra to solve for cherries ("c"). Algebra process shown below:

\frac{Cherries}{Lemons}=\frac{4}{9}=\frac{c}{45}\\9*c=4*45\\9c=180\\c=\frac{180}{9}\\c=20

See, we have the same answer, 20 cherries!

5.

Number sold total = 14 + 27 + 45 = 86

She still has 73 in her stock

So, she basically started with whatever she now has (73) and whatever she has sold the 3 days (86), that would be:

73 + 86 = 159 bracelets

Tia started with 159 bracelets

4 0
4 years ago
Hey i need help with number 8 and 9 thanks!
snow_lady [41]

Answer:

8     9.8 - 6.4n

9      15 - j/2

Step-by-step explanation:

8

2.8 - 4.4n - 2n +7

= 2.8+7 -4.4n -2n

= 9.8 - 6.4n

9

11 + (-3) - 1/8 j - 3/8 j +7

= 11 - 3 - 1/8 j - 3/8 j + 7

= 11 - 3 + 7 - 1/8 j - 3/8 j

= 15 - 4/8 j

= 15 - j/2

5 0
3 years ago
Write a description of how a diagram can help you solve 2x40
Tatiana [17]
I think the answer to your question is 80 I’m not sure how old this was any help
6 0
3 years ago
Help explain how pls
jok3333 [9.3K]

Answer:

Im not sure about it.

Step-by-step explanation:

First make the y on a side alone without anything by multiplying both sides by 2 then dividing by three, then substitute the x by the x value of x represented in the ordered pairs, and if the the result was the same value for y as represented in the ordered pair, then the ordered pair is correct.

7 0
2 years ago
81 POINTS
Jobisdone [24]

Base Case: plug in n = 1 (the smallest positive integer)

If n = 1, then 3n-2 = 3*1-2 = 1. Square this and we see that (3n-2)^2 = 1^2 = 1

On the right hand side, plugging in n = 1 leads to...

n*(6n^2-3n-1)/2 = 1*(6*1^2-3*1-1)/2 = 1

Both sides are 1. So that confirms the base case.

-------------------------------

Inductive Step: Assume that

1^2 + 4^2 + 7^2 + ... + (3k-2)^2 = k*(6k^2-3k-1)/2

is a true statement for some positive integer k. If we can show the statement leads to the (k+1)th case being true as well, then we will have sufficiently proven the overall statement to be true by induction.

1^2 + 4^2 + 7^2 + ... + (3k-2)^2 = k*(6k^2-3k-1)/2

1^2 + 4^2 + 7^2 + ... + (3k-2)^2 + (3(k+1)-2)^2 = (k+1)*(6(k+1)^2-3(k+1)-1)/2

k*(6k^2-3k-1)/2 + (3(k+1)-2)^2 = (k+1)*(6(k^2+2k+1)-3(k+1)-1)/2

k*(6k^2-3k-1)/2 + (3k+3-2)^2 = (k+1)*(6k^2+12k+6-3k-3-1)/2

k*(6k^2-3k-1)/2 + (3k+1)^2 = (k+1)*(6k^2+9k+2)/2

k*(6k^2-3k-1)/2 + 9k^2+6k+1 = (k+1)*(6k^2+9k+2)/2

(6k^3-3k^2-k)/2 + 2(9k^2+6k+1)/2 = (k*(6k^2+9k+2)+1(6k^2+9k+2))/2

(6k^3-3k^2-k + 2(9k^2+6k+1))/2 = (6k^3+9k^2+2k+6k^2+9k+2)/2

(6k^3-3k^2-k + 18k^2+12k+2)/2 = (6k^3+9k^2+2k+6k^2+9k+2)/2

(6k^3+15k^2+11k+2)/2 = (6k^3+15k^2+11k+2)/2

Both sides simplify to the same expression, so that proves the (k+1)th case immediately follows from the kth case

That wraps up the inductive step. The full induction proof is done at this point.

7 0
4 years ago
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