Question

The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal. 59) Initially, in terms of tonicity, the solution in side A with respect to that in side B is A) hypotonic. B) plasmolyzed. C) isotonic. D) saturated. E) hypertonic.

Answer 1

Initially, in terms of tonicity, the solution in side A with respect to that in side B is isotonic.

• A solution is considered to be isotonic if it possesses the same osmolarity, or level of solute concentration, as another solution. When these two solutions are placed on either side of a membrane that is only partially permeable to water, water will flow in an equal amount from one solution into the other. The result is that there is no water flow at all between the two solutions, despite the fact that water is travelling in both directions.

• A solution is considered hypotonic when it has a lower level of solute concentration in comparison to another solution.
• A solution is considered hypertonic when it has higher osmolarity compared to another solution.

In the given questions, the solution in the two arms of the U- tube has the same osmolarity and therefore is isotonic.

Learn more about the isotonic solution here :

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