The correct answer is B. The parents are heterozygous with polka-dot tails, so they both have Pp genotype. The combination of their genotypes (Pp x Pp) could produce 4 genotypes PP, Pp, Pp and pp. Therefore, there is 25% chance for a PP genotype, 25% for a pp genotype and 50% for a Pp genotype. The PP and Pp genotypes produce a polka-dot tail phenotype and the pp genotype produces a solid coloured tail phenotype. In conclusion, there is 75% chance for a polka-dot tail (25% for a PP + 50% for a Pp) and a 25% for a solid coloured tail phenotype (25% for a pp).
Answer:
The correct answer is D. levator scapulae.
Explanation:
The levator scapulae is the muscle involved in the scapula lifting, as it's located on the sides and back of the neck. As the person's head is protruding forward it's highly possible that the muscle involved is the <em>levator scapulae. </em>
Answer:
The correct answer is - option C.
Explanation:
CFTR is a short form of cystic fibrosis transmembrane conductance regulator protein which is caused by a recessive mutation in this protein. This mutation results in the accumulation of mucus in secretory organs.
As the disease is a recessive disease, for the mutant phenotype to expressed both copies of the allele required to be recessive.
The mother is negative for the CFTR. Hence, she will not transfer the mutant allele to her child So, the child would have a wild-type phenotype even if the father having two copies of recessive allele.
Thus, the correct answer is - option C.
b) some bacteria reduce nitrate ion
Answer:
here.
Explanation:
Due to the prevalence of malaria in Africa, the allele for sickle cell anemia (HbS) provides a selective advantage. That's why it remains in the population.
A normal African person (HbAHbA), with normal haemoglobin, will not die of anemia, but will die of malaria.
An African person with sickle cell anemia (HbSHbS), with abnormal haemoglobin, will die of anemia.
A heterozygous African person (HbAHbS), with half of his red blood cells (RBCs) being normal and the other half being sickle-shaped, will neither die from anemia, nor malaria since the plasmodium will be incapable of completing its life cycle in the abnormal RBCs.
Thus heterozygous African people will grow, reproduce and pass on the HbS allele to the next generations.
