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Vera_Pavlovna [14]
2 years ago
11

Simplify b^10/b^2 A. b^5 B. b^-5 C. b^8 D. b^-8

Mathematics
2 answers:
Art [367]2 years ago
8 0

Answer:

C.  b^8.

Step-by-step explanation:

b^10/b^2     We subtract the exponents:-

= b^(10-2)

= b^8.

kolezko [41]2 years ago
7 0

b^8

Step-by-step explanation:

b^10/b^2 ,. b^10-2 ;. b^8

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If y varies directly as x and y=3 when x=2 find y when x=8​
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Answer:

12

Step-by-step explanation:

x=2 was multiplied by 4 to get to x=8 so you multiply y=3 by 4 to make it y=12

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3 years ago
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I’m a bit confused on how to solve this problem, and could use some help!
weqwewe [10]

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Step-by-step explanation:

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3 years ago
Find all unit vectors that are orthogonal to the vector u = 1, 0, −4 .
KIM [24]

Answer:

Step-by-step explanation:

Given:

u = 1, 0, -4

In unit vector notation,

u = i + 0j - 4k

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If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then

u. v = 0                    [<em>substitute for the values of u and v</em>]

=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k)  = 0               [<em>simplify</em>]

=> v₁ + 0 - 4v₃ = 0

=> v₁ = 4v₃

Plug in the value of v₁ = 4v₃ into vector v as follows

v = 4v₃ i + v₂ j + v₃ k              -------------(i)

Equation (i) is the generalized form of all vectors that will be orthogonal to vector u

Now,

Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

\frac{v}{|v|}

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|v| = \sqrt{(4v_3)^2 + (v_2)^2 + (v_3)^2}

|v| = \sqrt{17(v_3)^2 + (v_2)^2}

\frac{v}{|v|} = \frac{4v_3i + v_2j + v_3k}{\sqrt{17(v_3)^2 + (v_2)^2}}

This is the general form of all unit vectors that are orthogonal to vector u

where v₂ and v₃ are non-zero arbitrary real numbers.

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3 years ago
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Answer:

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