Answer:
So the number of total combinations is 35.
Step-by-step explanation:
We know that Ellen must take 4 courses this semester. She has a list of 3 math courses and 4 science courses.
Therefore, she have total 7 courses.
So, we calculate the number of combinations to choose 4 out of 7 courses.
We get:

So the number of total combinations is 35.
No, she will not have enough. If you estimate the amount of money it will cost for the turkey sandwich and the large drink, it will cost about $7. She will only have $6.25 after admission costs.
The dominant term is -2x⁴.
As X approaches infinite, y is naturally going to be really large as well.
Remember that a number with an even exponent, regardless of whether it's positive or negative, will be positive.
As x approaches infinite, y will approach -2 * ∞, or -∞. Therefore, the end behavior in the positive direction is y=-∞
As x approaches negative infinite, y will approach -2 *∞ again. This is because -∞⁴ = ∞. Therefore, the end behavior in the negative direction is also y=-∞
Basically, due to the dominance of the -2x^4 term, the function will look more or less like a downward facing parabola with a y-intercept of 3.
The quadratic equation with roots a and b is given by:

Here a=1/2 and b=-4.
So the equation is given by:

The quadratic equation is as shown above.