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Arisa [49]
1 year ago
14

The volume of a certain right circular cone is 30 cubic inches. What is the volume, in cubic inches, of a second right circular

cone with half the radius and twice the height of the first cone
Mathematics
1 answer:
mrs_skeptik [129]1 year ago
3 0

Answer:

V = 15 in.³

Step-by-step explanation:

The original cylinder has radius r and height h.

V = πr²h

Its volume is 30 in.³, so

πr²h = 30 in.³

The new cylinder has radius (1/2)r and height 2h.

Its volume is

V = π(r/2)²(2h)

V = πr² × 2h/4

V = πr²h/2

πr²h is the volume of the original cylinder, and it is 30 in.³.

V = 30 in.³/2

V = 15 in.³

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valkas [14]

Answer:

x=1

Step-by-step explanation:

3x+3=5+x

3x-x+3=5

2x=2

x=1

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3 years ago
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Look at this graph:
andreev551 [17]

Answer:

The slope is 2/1.

Step-by-step explanation:

y2 - y1 /x2 - x1

6 - 4/ 2 - 1

2/1

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3 years ago
Does anyone know this??
blagie [28]

Answer:

x = 38, y = 4

Step-by-step explanation:

Since AB = BC  then the triangle is isosceles and the base angles are congruent, that is

∠ DAB = ∠ DCB = 52°

Subtract the sum of the base angle from 180° for ∠ ABC

∠ ABC = 180° - (52 + 52)° = 180° - 104° = 76°

Note that ∠ ABD = ∠ CBD, thus

x = 76 ÷ 2 = 38

BD bisects the side AC, thus DC = AD = 4

Thus y = 4

5 0
3 years ago
If the graph of f(x) = x^2, how will the graph be affected if it is changed to f(x) = 3r^2?
Eva8 [605]

Answer:

the graph curve will goes above f(x)=x^2.f(x)=3*x^2 curve will also give higher value same value of x .

Step-by-step explanation:

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3 years ago
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A line passes through the points (-3, 14) and (-1, 16). What is its equation in slope-intercept form?​
timurjin [86]

Answer:

y = 6x + 22

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-3, 14)

Point (-1, 16)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{16-14}{-1+3}
  2. Subtract/Add:               m=\frac{12}{2}
  3. Divide:                           m=6

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = 6x + b
  2. Substitute:              16 = 6(-1) + b
  3. Multiply:                  16 = -6 + b
  4. Isolate <em>b</em>:                 22 = b
  5. Rewrite:                   b = 22

<u>Step 4: Write linear equation</u>

y = 6x + 22

5 0
3 years ago
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