Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5
Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.
1+2+3= 6 (even)
2+3+4= 9 (odd)
it can be both
Answer:
1.59 < 1.73 < 2.061 < 2.1
Step-by-step explanation:
Hello,
We know that 2 is higher than 1. So to pick the first ones we know it won't be the two numbers starting with a 2. We are left with two numbers : 1.73 and 1.59. <u>In this case we can multiply these two numbers by 100. We are allowed to do this only if we do it to all the numbers we are trying to figure out.</u> In this case, it is 1.73 and 1.59 (we are excluding the 2s). So we end up with : 173 and 159. This might help you. We obviously know that 173 is a larger number than 159.
So, we then proceed to the numbers starting with a 2. <u>In this case we can multiply both by 1,000 considering the fact that the number 2.061 has 3 digits after the dot.</u> This will make it easier for us. When we multiply both by 1,000 we end up with 2,061 and 2,100. We obviously know that 2,061 is smaller than 2,100.
I hope this helped
Kind regards,
Clém
Answer:
As I answered your question, answer is D
Step-by-step explanation:
