Hello there!
The answer is C.
I will explain to you how I came to this answer.
•First of all, I counted the turning points. There are two, so that means this polynomial function has THREE roots. (# of turning points+1=number of roots.)
•Next, look to see how many times the function crosses the x-axis. This is the number of REAL solutions. In this case, there is one point at which the f(x) is crossing the x-axis so there is one real solution.
•Since there is one real solution there has to be 2 imaginary roots. (Total # of solutions-real solutions=imaginary solutions)
NOTE: the turning points are where the increasing intervals change to decreasing and the decreasing change to increasing. The first derivative at these points is 0.
I hope this helps!
Best wishes~
-HuronGirl
Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.
Since, perimeter is the total length of the outer boundary of the figure. Therefore,
Perimeter of the polygon is
Area of the polygon = Area of Rectangle + Area of Triangle
![=[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]](https://tex.z-dn.net/?f=%3D%5B%2818%29%20%5Ctimes%20%2815%29%5D%20%2B%20%5B%28%5Cfrac%7B1%7D%7B2%7D%29%20%5Ctimes%20%288%29%20%5Ctimes%20%2815%29%5D)
![=270 + [(\frac{8}{2}) \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B%28%5Cfrac%7B8%7D%7B2%7D%29%20%5Ctimes%20%2815%29%5D)
![=270 + [4 \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B4%20%5Ctimes%20%2815%29%5D)
The answer is b hope this helps
1. What is the total mass of the items in the wheel barrow?
9300g
2. What’s the mass of items, in kg, left in the barrow?
4.9kg
