Question

Find the seventh term of the sequence which has a first term of 1/2 and has a common ratio of three

Answer 1

The seventh term of the sequence is 364.5

Geometric progression

From the question, we are to determine the seventh term of the sequence

Using the formula,

$a_{n} = ar^{n-1}$

Where $a_{n}$ is the nth term

a is the first term

and r is the common ratio

From the given information,

a = 1/2

r = 3

Thus,

$a_{7} = (\frac{1}{2}) 3^{7-1}$

$a_{7} = (\frac{1}{2}) 3^{6}$

$a_{7} = \frac{1}{2} \times 729$

$a_{7} = 364\frac{1}{2} \ OR \ 364.5$

Hence, the seventh term of the sequence is 364.5

Learn more on Geometric progression here: brainly.com/question/24643676

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