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2 years ago

Triangle A B C. Side A B is 4, B C is 5, A C is 3. Triangle A prime B prime C prime.

Mathematics

1 answer:

madam [21]2 years ago

8 0

Answer:

The correct answer is 15.

Step-by-step explanation:

We are given that the original sides BC is 5. To find the length of B'C' we take the side of BC and multiply it by the scale factor.

5 (original BC) x 5 (the given scale factor) = 15

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Which is a number that can be written as a fraction in the form /?

mel-nik [20]

Answer:

the third one/second one

Step-by-step explanation:

7 0

3 years ago

Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long

Ne4ueva [31]

We are given

Jim's backyard:

Length is

$L=15\frac{5}{6} =\frac{95}{6} yards$

width is

$W=10\frac{2}{5} =\frac{52}{5} yards$

Since, this is rectangle

so, we can find area of rectangle

$A=L*W$

$A=(\frac{95}{6})*(\frac{52}{5})$

$A=\frac{494}{3} yard^2$

Area of one sod:

length is

$l=1\frac{1}{3} =\frac{4}{3} yards$

width is

$w=1\frac{1}{3} =\frac{4}{3} yards$

Since, it is rectangle in shape

so,

$Area=l*w$

$A=\frac{4}{3}*\frac{4}{3}$

$A=\frac{16}{9}yard^2$

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

$N=\frac{\frac{494}{3} }{\frac{16}{9} }$

now, we can simplify it

$N=\frac{741}{8}$ pieces need ..............Answer

7 0

3 years ago

Solve the equation 8y + 4x=5 for y. Oy=32x + 40 0 y = 40 – 32x o y= J +3 5. o y=

Liono4ka [1.6K]

Answer:

The Last One

Step-by-step explanation:

8y = 5 - 4x

y = 5/8 - (1/2)x

5 0

2 years ago

What is the standard form formula

vazorg [7]

Answer: The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers.

Explanation:

We can convert a point slope equation into standard form by moving the variables to the left side of the equation.

8 0

3 years ago

Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis

Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line $\overline{AA'}$ as the dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$ .

7 0

3 years ago