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Vesnalui [34]
3 years ago
9

What is the answer?(math)

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Option 4

Expression that represent the approximate amount of people the smaller stadium can hold is 6.75 \times 10^5

<em><u>Solution:</u></em>

Given that larger stadium can hold 4.5 \times 10^4 people which is about 15 times as many people as the smaller stadium can hold

To find: Expression that represent the approximate amount of people the smaller stadium can hold

From given information,

Number of people larger stadium hold = 15 times as many people as the smaller stadium can hold

Number of people larger stadium hold = 15 x (Number of people smaller stadium hold)

\rightarrow 4.5 \times 10^4 \times 15\\\\\rightarrow 67.5 \times 10^4

Which can also be expressed as:

To convert to scientific notation:

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

If you did not need to move the decimal b = 0.

Write your scientific notation number as a x 10^b and read it as "a times 10 to the power of b."

\rightarrow 67.5 \times 10^4 = 6.75 \times 10^5

So option 4 is correct

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4 0
3 years ago
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

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width: w

diagonal: (2w + 59) + 2  = 2w + 61

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(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

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a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

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since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

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Step 2: Add the areas together

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Hope this helps!! :)

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