Question

Measure of arc CF

Answer 1

Answer:

Step-by-step explanation:

The measure of an angle formed by a Secant and a tangent drawn from the outside point of a circle is half the difference of the intercepted arcs.

   $\sf \angle E =\dfrac{arc \ CF - arc \ DF}{2}$

        $\sf53 =\dfrac{arc \ CF-41}{2}$

  53*2  = arc CF - 41

   106    = arc CF - 41

106 + 41 = arc CF

   $\sf \boxed{\bf \ arc \ CF = 147^\circ}$

9)  If two secants inside a circle, then the angle formed is equal to the half of the sum of intercepted arcs.

    $\sf 5x - 7 = \dfrac{27+119}{2}\\\\ 5x - 7 = \dfrac{146}{2}$

   5x - 7  = 73

         5x = 73 + 7

         5x = 80

           x = 80/5

          $\sf \boxed{\bf \ x = 16^\circ }$