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Crazy boy [7]
3 years ago
14

A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. Find the value that is –2 standard devi

ations away from the mean.
Mathematics
2 answers:
dybincka [34]3 years ago
6 0
45+8.3 = 53.3 

<span>45 - (2(8.3)) = 28.4

The value is </span> 28.4 <span>that is –2 standard deviations away from the mean.</span><span>

</span>
Kamila [148]3 years ago
4 0

Answer: 28.4

Step-by-step explanation:

Given : A set of data with a mean of \mu= 45and a standard deviation of  \sigma=8.3 is normally distributed.

Now, the value that is –2 standard deviations away from the mean is given by :-

x=\mu-2\sigma\\\\\Rightrrrow\ x=45-2(8.3)\\\\\Rightarrow\ x=45-16.6\\\\\Rightrrrow\ x=28.4

Hence, the value that is –2 standard deviations away from the mean. = 28.4

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20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

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