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andreev551 [17]
2 years ago
7

the vertex of this parabola is at (-5,-2) when the x value is -4 the y value is 2 . what is the coefficient of the squared expre

ssion in the parabola's equation
Mathematics
1 answer:
saw5 [17]2 years ago
3 0

The <em>vertex</em> coefficient of the parabola with vertex (- 5, - 2) and the point (- 4, 2) is equal to 1.

<h3>What is the vertex coefficient of the equation of the parabola?</h3>

In this question we must find the <em>vertex</em> coefficient of the equation of the parabola, which is the <em>vertex</em> form of the <em>quadratic</em> equation:

y - k = C · (x - h)²

If we know that (h, k) = (- 5, - 2) and (x, y) = (- 4, 2), then the vertex coefficient is:

2 - (- 2) = C · [- 4 - (- 2)]²

4 = C · (- 2)²

C = 1

The <em>vertex</em> coefficient of the parabola with vertex (- 5, - 2) and the point (- 4, 2) is equal to 1.

To learn more on parabolas: brainly.com/question/4074088

#SPJ1

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15 inches of snow fell in 12 hours. At this rate, how many inches of snow will fall in 3 days.
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3 years ago
Read 2 more answers
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Solve for x please help me
stepladder [879]

Answer:

4

Step-by-step explanation:

By intersecting chords theorem:

12x = 3(x + 12) \\  \\ 12x = 3x + 36 \\  \\ 12x - 3x = 36 \\  \\ 9x = 36 \\  \\ x =  \frac{36}{9}  \\  \\ x = 4

6 0
3 years ago
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