Solving a system of equations we can see that the two numbers are 727 and 4
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How to find the two numbers?</h3>
Let's define x as the 3-digit number and y as the one-digit number.
Then we know that the sum is equal to 731:
x + y = 731
And the product is equal to 2,908, then:
x*y = 2,908
So we have a system of equations:
x + y = 731
x*y = 2,908
Isolating x on the first equation gives:
x = 731 - y
Now we can replace that in the other equation to get:
(731 - y)*y = 2,908
Now we can solve this quadratic equation to find the value of y.
731*y - y^2 = 2,908
-y^2 + 731*y - 2,908 = 0
The solutions are:
y = (-731 ± √( 731^2 - 4*(-2,908)*(-1))/(-2)
y = (-731 ± 723)/-2
Now, y is an one digit number, then:
y = (-731 + 723)/-2 = 4
And x will be the 3 digit number:
x = 731 - x = 731 - 4 = 727
So the two numbers are 727 and 4
Learn more about systems of equations:
brainly.com/question/13729904
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