Answer:
The picture is blocked out D:
Step-by-step explanation:
The total amount raised is the sum of the amounts raised by the car wash and the dinner. The car wash raised 7c - 18. The dinner raised 6s - 45. We now add the expressions and combine like terms.
7c - 18 + 6s - 45
We need to combine like terms. Like terms are terms that have the same variables and the same exponents on the variables. 7c and 6s are not like terms since c and s are different variables. They cannot be combined together. Plain numbers, like -18 and -45 are lime terms because their variable parts are the same; they both have no variables.
7c - 18 + 6s - 45 =
= 7c + 6s - 18 - 45
= 7c + 6s - 63
Answer: C. 7c + 6s - 63
-0.6875 is the answer to number 5
Remark
You need 2 facts to solve this
1. The area of a hexagon is
A = 3*(sqrt(3) ) * a^2/2
Just to make this clear, I'll put it in Latex
2. The second fact you need to know is that the radius = the length of the side a.
Givens
r = 20 in
a = r where a is the length of the side of a hexagon.
Formula Substitute and solve.
A = 3*(sqrt(3) * a^2 ) / 2
A = 3*(sqrt(3) * 20^2) / 2
A = 3*sqrt(3) * 400 / 2
A = 3*sqrt(3) * 200
A = 3*1.7321 * 200
A = 1039 square inches.
Answer:
- 273 mL of 5%
- 117 mL of 15%
Step-by-step explanation:
Let q represent the quantity of 15% dressing used. Then the amount of 5% dressing is (390 -q). The amount of vinegar in the mix is ...
0.15q + 0.05(390 -q) = 0.08(390)
0.10q = 31.2 -19.5 = 11.7 . . . . . . subtract 0.05(390) and simplify
q = 117 . . . . . . . . . . . . . . . . . . multiply by 10
390-q = 273
The chef should use 273 mL of the first brand (5% vinegar) and 117 mL of the second brand (15% vinegar).
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<em>Additional comment</em>
You may have noticed that the value of q is (0.08 -0.05)/(0.10 -0.05)×390. The fraction of the mix that is the highest contributor is the ratio of the difference between the mix value and least contributor, divided by the difference between the contributors: (8-5)/(15-5) = 3/10, the fraction that is 15% vinegar. This is the generic solution to mixture problems.
