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Agata [3.3K]
4 years ago
11

If 6x -1 = 29, what is the value of x² + x?

Mathematics
2 answers:
irina1246 [14]4 years ago
7 0

Answer: <em>The answer would be x (x+1)</em>

bija089 [108]4 years ago
6 0
29+1=30
30\6=5
X=5
52=25+5=30
Answer=30
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Need asap! graph the inverse of the function shown. use the drawing tools to form the correct answer on the graph.
777dan777 [17]

Answer:

Step-by-step explanation:

5 0
3 years ago
Z +5 = 6<br> Help please
Phoenix [80]

Answer:

z = 1

Step-by-step explanation:

z + 5 = 6

z = 6 - 5

z = 1

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6 0
3 years ago
Read 2 more answers
Help please anything
Nat2105 [25]

Answer:

36 ft

Step-by-step explanation:

The ratio of the lengths of the sides is the same as the ratio of the perimeters.

Just like one side (15 ft) of triangle ABC is 3 times as long as the corresponding side (5 ft) of triangle DEF, the perimeter of triangle ABC is also 3 times the perimeter of triangle DEF.

15/5 = x/12

3 = x/12

x = 36

Answer: 36 ft

7 0
3 years ago
-0.2×-5/7<br><br>please can i have some help
Ksivusya [100]

Answer:

+1/7

Step-by-step explanation:

One approach to evaluating this would be to rewrite it as:

-2        -5  

------ * --------- .  

 10          7   This reduces to:

 2

--------- = +1/7

 2(7)

8 0
4 years ago
A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

4 0
3 years ago
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