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1 year ago

Please help me it is easy I just dont understand

Mathematics

1 answer:

postnew [5]1 year ago

4 0

Answer:

13%

15%

41%

31%

Step-by-step explanation:

To find the percentage one amount is out of another amount, divide the smaller amount by the bigger amount. You will end up with a decimal (0.xy where x is the 10% place and y is the 1% place).

For example: to find the percentage that 39 is out of 300 students, we divide 39 by 300. This gives us the decimal 0.13. Written as a percentage, that is 13%.

We can do this for all of them.

Here is the math for each one:

39 ÷ 300 = 0.13 → 13%

45 ÷ 300 = 0.15 → 15%

123 ÷ 300 = 0.41 → 41%

93 ÷ 300 = 0.31 → 31%

Once you have all these decimals, you might choose to check your work by adding them up. They should at up to 1.00, or 100%. In this case, they do, so we know these answers are correct.

I hope this helps. Please let me know if you have questions.

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A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 respon

Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14% chose chocolate pie, and the margin of error was given as plus or minus ±3 percentage points.

The pivotal quantity for the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who chose chocolate pie = 14%

n = sample of adults = 500

p = true proportion

Now, the 99% confidence interval for p = $\hat p \pm Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

Here, $\alpha$ = 1% so $(\frac{\alpha}{2})$ = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.03 for 99% interval.

So, 99% confidence interval for p = $0.14 \pm2.5758 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

= [0.14 - 0.03 , 0.14 + 0.03]

= [0.11 , 0.17]

Similarly, 80% confidence interval for p = $0.14 \pm 1.2816 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

Here, $\alpha$ = 20% so $(\frac{\alpha}{2})$ = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.02 for 80% interval.

So, 80% confidence interval for p = [0.14 - 0.02 , 0.14 + 0.02]

= [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0

3 years ago

I need help with my mathematics exam grade 7 end year!PLEASE help me asap!!PLEASE i beg you :)

AnnyKZ [126]

so first off for the ratios

if you were to find them on a graph, you would want to find a slope. The slope is your ratio pretty much

if you were to find them for a table, you would have to see what the question is asking. if it asking like what is the amount of people vs animals per square mile, you would find people on the table and then go down to square mile as opposed to square feet or some other variable. Then you will put what they are asking first and then what they are asking second. here ill show you an example if it is to confusing what i just said. if there are 50 animals per square mile and 150 people per square mile, and the question asked you what is the ratio between people and animals, you would answer 150/50, BUT you have to simplify. 3/1 would be you answer.

next off for the transformation

if there was a triangle at the points 5,3|4,6|5,5| and you wanted to translate it 5 units up and 6 units to the left, all you do is think about this. up and down are changes in the y, left and right are changes in the x axis. left and down are negative changes, up and right are positive changes.

so you would apply that thinking to ALL the points. it would look something like the picture below.

finally, for the shaded area of figures

lets take a abstract figure. say that we shade the upper left hand corner, and it will look something like the picture below. If you want to find the area of the figure, you would have to isolate it. Then you would multiply the width by the length and get 2.

i really hope this helps on your exam. good luck!