Answer:
Step-by-step explanation:
At the end of any given business day, CFFC has 400-80t cases of perfume on hand, where t = 1 represents Monday, t = 2 represents Tuesday and so on. The inventory becomes nil on Friday evening. So,
The values of a and b are
a = 0
b = 5
Using the formular for average value, we have the average value as
Average inventory is 200 cases
Answer:
32 33-cent stamps, 8 23-cent stamps
Step-by-step explanation:
In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).
Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.
To make our first equation, let's think about the number of stamps total we have. We can say:
<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>
Now, let's make an equation for the cost of these stamps.
<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>
So now, we have our two equations:
If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.
If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.
Now, let's put this into our second equation.
Distribute, and solve for y.
Now, we plug this into one of our equations.
In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.
Answer:
See the proof below.
Step-by-step explanation:
What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where . If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"
Proof
Since we have a if and only if w need to proof the statement on the two possible ways.
If X is linearly dependent, then a vector is a linear combination
We suppose the set is linearly dependent, so then by definition we have scalars
in C such that:
And not all the scalars are equal to 0.
Since at least one constant is non zero we can assume for example that , and we have this:
We can divide by c1 since we assume that and we have this:
And as we can see the vector can be written a a linear combination of the remaining vectors
. We select v1 but we can select any vector and we get the same result.
If a vector is a linear combination, then X is linearly dependent
We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select and we have this:
For scalars defined in C. So then we have this:
So then we can conclude that the set X is linearly dependent.
And that complet the proof for this case.