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Stels [109]
3 years ago
7

HELP ASAP!

Mathematics
1 answer:
sveta [45]3 years ago
4 0
Area of rectangle = 36 x 20 = 720 ft^2

Perimeter of rectangle = 2(36 + 20) = 112 ft

Area of semi-circle = 1/2πr^2 (r = 18/2 = 9, using π = 3.14<span>)
= 1/2 x 3.14 x 9^2
= 142.87 ft^2

</span>Perimeter of semi-circle = πd = 3.14 x 18 = 56.52 ft

<span>(a) What is the total area of the swimming pool? Explain your reasoning.
</span>
area of the swimming pool = area of rectangle - area of semi-circle
area of the swimming pool = 720 ft^2 - 142.87 ft^2 = 577.13 ft^2

answer:
area of the swimming pool = 577.13 ft^2

--------------------------------------------------------------------------
<span>(b) What is the perimeter of the swimming pool? Explain your reasoning.
</span>perimeter of the swimming pool = perimeter of rectangle - perimeter of semi-circle
perimeter of the swimming pool = 112 ft - 56.52 ft = 55.48 ft

answer
perimeter of the swimming pool = 55.48 ft
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Answer: x intercept = 6

This is the location (6,0)

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Explanation:

I assume you're talking about the boundary line of the inequality. The boundary line equation is 2x + 3y = 12

To find the x intercept, plug in y = 0 and solve for x

2x + 3y = 12

2x + 3(0) = 12

2x = 12

x = 12/2

x = 6

The boundary line 2x+3y = 12 crosses the x axis at x = 6.

We can say the x intercept is x = 6. This is the location (6,0).

Side note: the y intercept is y = 4, which is found by plugging in x = 0 and solving for y.

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Step-by-step explanation:

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A BASKETBALL PLAYER MAKES A BASKET THROUGH A TEN FOOT HIGH BASKET FROM 20 FEET AWAY. IF THE SHOOTER RELEASES THE BALL FROM 8 FEE
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Answer:

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The vertical velocity of the ball in the basket = 8.81 m/s

Step-by-step explanation:

The given parameters are;

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The horizontal location of the shooter from the basket = 20 feet

The height from which the shooter releases the ball = 8 feet

The horizontal velocity of the ball = 10 ft/s

Therefore, we have;

Time, t = Horizontal distance/(Horizontal velocity)

t = 20/10 = 2 seconds

The vertical velocity is given as follows;

s = u·t - 1/2·g·t²

Where;

u = The vertical velocity

s = The height above the initial height from which the ball is released

s = y - y₀

Where;

y = The final height of the ball in the calculation = The height of the basket = 10 foot

y₀ = The initial height from which the ball is released = 8 feet

∴ s = 10 - 8 = 2 feet

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Substituting gives;

2 = u × 2 - 1/2 × 9.81× 2²

u = (2 + 1/2 × 9.81× 2²)/2 = 10.81 m/s

The vertical velocity of the ball when released = 10.81 m/s.

The vertical velocity of the ball in the basket is given by the following relation;

v² = u² - 2·g·s

v² = 10.81² - 2×9.81×2 = 77.6161

v = √(77.6161) = 8.81 m/s

The vertical velocity of the ball in the basket = 8.81 m/s

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