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3 years ago

HELP ASAP!

Mathematics

1 answer:

sveta [45]3 years ago

4 0

Area of rectangle = 36 x 20 = 720 ft^2

Perimeter of rectangle = 2(36 + 20) = 112 ft

Area of semi-circle = 1/2πr^2 (r = 18/2 = 9, using π = 3.14)
= 1/2 x 3.14 x 9^2
= 142.87 ft^2

Perimeter of semi-circle = πd = 3.14 x 18 = 56.52 ft

(a) What is the total area of the swimming pool? Explain your reasoning.

area of the swimming pool = area of rectangle - area of semi-circle
area of the swimming pool = 720 ft^2 - 142.87 ft^2 = 577.13 ft^2

answer:
area of the swimming pool = 577.13 ft^2

--------------------------------------------------------------------------
(b) What is the perimeter of the swimming pool? Explain your reasoning.
perimeter of the swimming pool = perimeter of rectangle - perimeter of semi-circle
perimeter of the swimming pool = 112 ft - 56.52 ft = 55.48 ft

answer
perimeter of the swimming pool = 55.48 ft

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Answer:

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3 years ago

Ms. Wilmith bought 4 bags of candies. Each bag contained 8 candies. She put an

N76 [4]

Answer:

Number of candy left = 5

Step-by-step explanation:

Given:

Number of bags = 4

Number of candies in each bag = 8

Number of Gift boxes = 9

Find:

Number of candy left = ?

Computation:

Total number of candies = Number of bags × Number of candies in each bag

Total number of candies = 4 × 8

Total number of candies = 32

According to Euclid division lemma:

a = bq +r

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

In a previous poll, 40% of adults with children under the age of 18 reported that their family ate dinner together seven night

natali 33 [55]

Answer:

We conclude that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remained same.

Step-by-step explanation:

We are given that in a previous poll, 40% of adults with children under the age of 18 reported that their family ate dinner together seven nights a week.

Suppose that, in a more recent poll, 456 of 1194 adults with children under the age of 18 reported that their family ate dinner together seven nights a week.

Let p = proportion of families with children under the age of 18 who eat dinner together seven nights a week.

SO, Null Hypothesis, $H_0$ : p $\geq$ 40% {means that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remained same}

Alternate Hypothesis, $H_A$ : p < 40% {means that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has decreased}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of families with children under the age of 18 who eat dinner together seven nights a week = $\frac{456}{1194}$ = 0.38

n = sample of adults = 1194

So, the test statistics = $\frac{0.38-0.40}{\sqrt{\frac{0.38(1-0.38)}{1194} } }$

= -1.424

The value of z test statistics is -1.424.

Now, at 0.01 significance level the z table gives critical value of -2.326 for left-tailed test.

Since our test statistic is more than the critical value of z as -1.424 > -2.326, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of families with children under the age of 18 who eat dinner together seven nights a week has increased or remained same.

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4 years ago

How many liters of a 20% alcohol solution must be mixed with 60 liters of a 90% solution to get a 80% solution?

leva [86]

x = liters of 20% solution

Mixing the 20% solution with the 60 L of 90% solution gives a new mixture with volume (x + 60) L. Each L of the 20% solution contributes 0.2 L of alcohol and thus a total of 0.2x L of alcohol, while the 60 L of 90% solution contributes 54 L of alcohol.

We want the concentration of the new mixture to be 80%, so we require

$\dfrac{0.2x+54}{x+60}=0.8$