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Art [367]
4 years ago
12

A circle of a certain radius has an area which is numerically 5 times the value of the circumference. What is the radius of the

circle?
Mathematics
1 answer:
patriot [66]4 years ago
5 0

We have been given that a circle of a certain radius has an area which is numerically 5 times the value of the circumference. We are asked to find the radius of the circle.

We know that area of circle with a radius of r units is \pi r^2.

We know that circumference of a circle is 2\pi r.

5 times the value of circumference would be 5(2\pi r)=10\pi r.

Now we will equate 5 times circumference with area as:

\pi r^2 = 10\pi r

Let us solve for r.

\pi r\cdot r = 10\pi r

\frac{\pi r\cdot r}{\pi r}=\frac{10\pi r}{\pi r}

r=10

Therefore, the radius of the circle would be 10 units.

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Please correct both problems...and if I'm doing something PLEASE HELP,me ​
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Answer:

1. g(f(-2)) = -19

2.  f(f(-1)) = -1

Step-by-step explanation:

1. g(f(-2)) where f(x) = 5x + 2 and g(x) = 2x-3

you're on the right track! g(f(x)) means that g's x is equal to the function f, in which you would plug in the answer for f (or equation in some cases) and that would be the x term of g. g(f(x)) or (g°f) can be said as "g composed of f"

what i would do first to make it a bit more simpler is plug in -2 in f(x) and then plug in that answer into g(f(x))

f(-2) = 5(-2) + 2 = -10 + 2 = -8

f(-2) = -8

in your steps, you put g(-2) = -8, when it is f(-2) = -8,

what you would do after that is plug in -8 into g(f(x))

g(f(-8)) = g(-8) <-- plug in -8 for x in g(x)

g(-8) = 2(-8) - 3 <-- distribute 2 into -8

-16 - 3 = -19

so g(f(-2)) = -19

2. find f(f(-1)) when f(x) = 8 - x

first you want to solve f(-1)

f(-1) = 8 - (-1) = 9

so f(-1) = 9

again, what you did in this composition is solved for the first function (the inside f), but never plugged in the result into the second function

now we want to plug in the answer 9 into f(x)

f(9) = 8 - (9) = -1

so f(9) = -1

this leaves us with the answer: f(f(-1)) = -1

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