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Sav [38]
2 years ago
12

A map has the scale 2 inches equals 190 miles. The distance from Springfield to Glenview is 14 inches. How many actual miles sep

arate Springfield from Glenview? A. 140 B. 1,330 C. 2,800 D. 38
Mathematics
1 answer:
Kay [80]2 years ago
8 0
Lord help me hdbdbdbdbfbbfbfbrbbdbdbdbdnrjbdbdbdbdbdbdbhdhrbtbrbdbdbbrrbrgrggrgrhhrhr
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Show that (2+3) + 6= (6+3) +2
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Answer: use order of operstions

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Ari is designing a
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To find the ratio, you Will need to find the ratio of the patio, and the ratio of the scale version of the patio.

16 feet x 20 feet = 320 ft.²

(16/4 = 4 in)/(20/4= 5 in)

4 inches x 5 inches = 20 in.²

320 ft.² / 20 in.² = 16 ft.² / 1 square inch

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use the substitution method to solve the system of equations. Choose the correct ordered pair. y=4x 8x+y=18
tino4ka555 [31]

Answer:

(3/2, 6)

Step-by-step explanation:

y = 4x

8x + y = 18

this says y is 4x so you can replace y with 4x

8x + 4x = 18

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/12      /12

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3 years ago
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Write an equation that describes the function.
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4x is the proportionality
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2 years ago
The frequency distributions of two data sets are shown in the dot plots below.
fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

\text{Mean of data set 1}=\frac{45}{19}

\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0
3 years ago
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