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antiseptic1488 [7]
2 years ago
8

Wright in point-slope form, slope-intercept form and in standard form an equation that passes through (-1, 2) with slope 4

Mathematics
2 answers:
SOVA2 [1]2 years ago
8 0

Answer:

\textsf{Point-slope form}: \quad \sf y-2=4(x+1)

\textsf{Slope-intercept form}: \quad \sf y=4x+6

\textsf{Standard form}: \quad \sf 4x-y=-6

Step-by-step explanation:

<u>Given information</u>:

  • Slope = 4
  • Point on line = (-1, 2)

<u>Point-slope form</u><u> of linear equation</u>:  

\sf y-y_1=m(x-x_1)

(where m is the slope and (x₁, y₁) is a point on the line)

Substitute the given slope and point into the formula:

\implies \sf y-2=4(x-(-1))

\implies \sf y-2=4(x+1)

<u>Slope-intercept form</u><u> of a linear equation</u>:

\sf y=mx+b

(where m is the slope and b is the y-intercept)

Substitute the given slope and point into the formula and solve for b:

\implies \sf 2=4(-1)+b

\implies \sf b=6

Therefore:

\sf y=4x+6

<u>Standard form</u><u> of a linear equation</u>:

\sf Ax+By=C

(where A, B and C are constants and A must be positive)

Rearrange the found slope-intercept form of the equation into standard form:

\implies \sf y=4x+6

\implies \sf 4x-y+6=0

\implies \sf 4x-y=-6

Learn more about linear equations here:

brainly.com/question/27317293

brainly.com/question/28062655

lora16 [44]2 years ago
8 0

<u>Point-slope form</u>

y-2=4(x+1)

<u>Slope-intercept</u><u> </u><u>form</u>

y-2=4x+4 \\ \\ y=4x+6

<u>Standard</u><u> </u><u>form</u>

4x-y+6=0

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