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Alexus [3.1K]
3 years ago
7

If only 4.5% of the non- historically protected have a field stone and mortar foundation, how many homes is this?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0
4.5% of 134....134 is the total of non-historically protected homes
0.045(134) = 6.03 which rounds to 6 <=
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Jackson bought 5 ounces of raisins for $4 dollar sign. How much do raisins cost per ounce?
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Answer:

Cost of raisin per ounce = $0.8

Step-by-step explanation:

Solution:

Number of ounces = 5 ounces

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Naily [24]

Answer:

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

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So the p value is a very high value and using the significance level provided \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation  

X_{1}=507 represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

n_{1}=32601 sample elected from arizona

\hat p_{1}=\frac{507}{32601} =0.0156 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

p_{2}=\frac{1}{88}= 0.0114 represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD)  in the nation

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis:p_{1} \leq p_{2}  

Alternative hypothesis:p_{1} > p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{507+1}{32601 +88}=0.01554  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318    

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Since is a one right sided test the p value would be:  

p_v =P(Z>0.318)=0.375  

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Serhud [2]

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