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VashaNatasha [74]
3 years ago
7

PLEASE SOLVE AND SHOW WORK Find the equation of the line that passes through the points (-1,-5) and (-7,-6) in slope intercept f

orm
Mathematics
1 answer:
Lynna [10]3 years ago
4 0
The way that you find this problem is to first find the slope, and then input one of your points into your equation to find b.
The slope-intercept form of a line is: y=mx+b, where m is the slope and b is the y-intercept.

To find the slope, you must use the following equation:
\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

In this equation, this would be equivalent to:\frac{-6-(-5)}{-7-(-1)} which, when simplified, is \frac{1}{6}. This is your slope.

To find the Y-intercept, you just plug all variables that you currently have solved for into the equation. You may use either point for the x and y variables, but you must use \frac{1}{6} for the m term.

-6 = (\frac{1}{6})(-7) + b leads to -6 = \frac{-7}{6} +b which leads to \frac{-29}{6} = b. You have now solved for the y-intercept and aare ready to form your final equation.

The final equation is:y=\frac{1}{6}x -\frac{29}{6}
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Using the discriminant, the quadratic equation that has complex solutions is given by:

x² + 2x + 5 = 0.

<h3>What is the discriminant of a quadratic equation and how does it influence the solutions?</h3>

A quadratic equation is modeled by:

y = ax² + bx + c

The discriminant is:

\Delta = b^2 - 4ac

The solutions are as follows:

  • If \mathbf{\Delta > 0}, it has 2 real solutions.
  • If \mathbf{\Delta = 0}, it has 1 real solutions.
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In this problem, we want a negative discriminant, hence the equation is:

x² + 2x + 5 = 0.

As the coefficients are a = 1, b = 2, c = 5, hence:

\Delta = 2^2 - 4(1)(5) = 4 - 20 = -16

More can be learned about the discriminant of quadratic functions at brainly.com/question/19776811

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