Answer:
Step-by-step explanation:
In any triangle, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse (longest side) of the triangle. (a/h)
The angle marked 40 degrees has an adjacent side of and the hypotenuse of the triangle is 60.
Therefore, we have the equation:
The solutions to the systems of inequalities are (0.3, 1.3), (-1, -2), (0.4, 1.8) and (3.6, 0.8)
<h3>How to determine the solution to the systems?</h3>The graph of the systems of inequalities is not given.
So, I would plot a new graph to answer this question.
The systems of inequalities are given as:
y − x > 1 and 2x + y ≤ 2
x + y ≥ -3 and 5x – y ≤ -3
2x – y ≤ -1 and x + 2y < 4
4x – 3y < 12 and x + 3y ≥ 6
Next, we plot these inequalities on a graph and write out the points of intersection.
From the attached graph, we have:
y − x > 1 and 2x + y ≤ 2 ⇒ (0.3, 1.3)
x + y ≥ -3 and 5x – y ≤ -3 ⇒ (-1, -2)
2x – y ≤ -1 and x + 2y < 4 ⇒ (0.4, 1.8)
4x – 3y < 12 and x + 3y ≥ 6 ⇒ (3.6, 0.8)
Hence, the solutions to the systems of inequalities are (0.3, 1.3), (-1, -2), (0.4, 1.8) and (3.6, 0.8)
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