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kupik [55]
2 years ago
8

(07.06) There are currently 4 people signed up to play on a baseball team. The team must have at least 9 players.

Mathematics
1 answer:
beks73 [17]2 years ago
8 0

A graph which includes the possible values for number of people who can still sign up for the team is: B. number line with closed circle on 5 and shading to the right.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains numerical values (positive and negative numbers) that are placed at equal intervals along its length.

Let the number of people who can still sign up for the team be represented by x. Thus, the inequality is given by:

x + 4 ≥ 9

x ≥ 9 - 4

x ≥ 5.

This ultimately implies that, there could be five (5) or more people that can still sign up for the team and a graph which includes these possible values is a number line with closed circle on five (5) and shading to the right because it can get larger.

Read more on number line here: brainly.com/question/24644930

#SPJ1

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Answer:

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The sides of a quadrilateral whose sides are 85cm 143cm 165cm and 85cm and one of the diagonals is 154cm
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Answer:85cm is kept comstant for a while

Step-by-step explanation:

For 2nd part

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Step-by-step explanation:

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3 years ago
I PROMISE BRAINLIST; 5-STARS; THANKS!! IT'S VERY SIMPLE; BELIEVE ME!!!!!
DochEvi [55]

Answer:

2. B

3. C

4. B

5. D

Step-by-step explanation:

2) The sequence is multiplying by -2 each time. This means that it is geometric.

The next two terms would be:

32*-2=-64\\-64*-2=128\\128*-2=-256

This means that the answer is B

3) The sequence is being multiplied by \frac{1}{3} each time. This means that it is geometric.

The next 3 terms would be:

3*\frac{1}{3} =1 \\\\1*\frac{1}{3} =\frac{1}{3} \\\\\frac{1}{3} *\frac{1}{3} =\frac{1}{9}

I am assuming that the answer is C and that you were unable to type the fractions.

4) We know that the common difference is 1.5, so that is the coefficient of our variable and the starting value is 15. This means that we can write an equation as follows

f(x)=1.5(x-1)+15

Now we can find the first 4 terms

f(1)=15.0\\f(2)=16.5\\f(3)=18.0\\f(4)=19.5

This would mean that the answer is B

5) We know that this is a geometric series, we know the common ratio, and we know the first term. This means we can write the equation as follows

f(x)=4.5(10)^{x-1}

Now we can find the first 4 terms

f(1)=4.5\\f(2)=45\\f(3)=450\\f(4)=4500

Unless you meant that the ratio was \frac{1}{10}, the answer is D, none of the above

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

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