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3 years ago

The solution for 7(5x+9)=12-(x+9) and simplified

Mathematics

1 answer:

Charra [1.4K]3 years ago

4 0

Answer:

x= -5/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7(5x+9)=12−(x+9)

7(5x+9)=12+−1(x+9)(Distribute the Negative Sign)

7(5x+9)=12+−1x+(−1)(9)

7(5x+9)=12+−x+−9

(7)(5x)+(7)(9)=12+−x+−9(Distribute)

35x+63=12+−x+−9

35x+63=(−x)+(12+−9)(Combine Like Terms)

35x+63=−x+3

Step 2: Add x to both sides.

35x+63+x=−x+3+x

36x+63=3

Step 3: Subtract 63 from both sides.

36x+63−63=3−63

36x=−60

Step 4: Divide both sides by 36.

36x/36 and -60/36

x= -5/3

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3 years ago

Solve for V<br> 1 - 5V = V + 9 – 10V

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Answer:

Step-by-step explanation:

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3 years ago

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r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

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Therefore the value of given expression is $\frac{21}{128}$ .

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3 years ago

Find the value of 5x - 2y+ 3z when x = 7 , y = 11 and z = -1

Oksanka [162]

By replacing you get:

5*7-2*11+3*(-1) = 35-22-3= 10

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3 years ago

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marissa [1.9K]

Answer:

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Step-by-step explanation:

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3 years ago

The solution for 7(5x+9)=12-(x+9) and simplified​

The solution for 7(5x+9)=12-(x+9) and simplified