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sweet-ann [11.9K]
2 years ago
9

There are 15 players on a volleyball team. Only 6 players can be on the court for a game. How many different groups of players o

f 6 players can the coach make, if the position does not matter?
Mathematics
1 answer:
stealth61 [152]2 years ago
8 0

There are 5005 different groups

<h3>How to determine the number of groups?</h3>

The given parameters are:

Players, n = 15

Selected, r = 6

The number of groups is then calculated as:

Group = ^{n}C_r

This gives

Group = ^{15}C_6

Apply the combination formula

Group = \frac{15!}{9!6!}

Evaluate the expression

Group = 5005

Hence, there are 5005 different groups

Read more about combination at:

brainly.com/question/11732255

#SPJ1

You might be interested in
All zeros of polynomial function 3x^4 +14x^2 -5
Marizza181 [45]

Answer:

Correct answer:  x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

Step-by-step explanation:

Given:

3 x⁴ + 14 x² - 5 = 0   biquadratic equation

this equation is solved by a shift  x² = t and get:

3 t² + 14 t - 5 = 0

t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6

t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6

t₁ = -5   or  t₂ = 1 / 3

the solution t₁ = -5 is not accepted because it cannot be x² = -5

we accepted  t₂ = 1 / 3

x² =  1 / 3  ⇒  

x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

God is with you!!!

5 0
3 years ago
Carey is trying to decide between two guitars. The first had an original price of $160, but is on sale for $100. The second had
Zolol [24]

Subtract the sale price from the original price then divide the difference by the original price.

Guitar 1: 160 -100 = 60

60/160 = 0.375 x 100 = 37.5%

Guitar 2: 250 - 150 = 100

100/250 = 0.4 x 100 = 40%

The answer is the second guitar has a greater percent change of approximately 40%

3 0
3 years ago
Read 2 more answers
Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

7 0
4 years ago
Need a quick answer please
Arlecino [84]

Answer:

search it up its there

Step-by-step explanation:

3 0
3 years ago
Which is a correct first step for solving this equation
rosijanka [135]

Answer:

see explanation

Step-by-step explanation:

given

- 3x + 2 - 5x - 7 = 4x + 2

The first step is to simplify the left side by collecting like terms

- 8x - 5 = 4x + 2


5 0
3 years ago
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