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3 years ago

I =125 r=6% t=1 what is p

Mathematics

1 answer:

vfiekz [6]3 years ago

4 0

There is no P in here, you can't solve for P without a P, Or I just don't get the question.

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There are 247 cities

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2 years ago

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A square hole 7.50 cm along each side is cut in a sheet of copper. (a) Calculate the change in the area of this hole resulting w

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Step-by-step explanation:

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2 years ago

What is the area of one of the triangular faces?

Naya [18.7K]

Answer: 6

Step-by-step explanation:

One of the triangular faces is 4*3= 12. Then 1/2 of 12 is 6.

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2 years ago

Recall the equation for a circle with center (h, k) and radius r. At what point in the first quadrant does the line with equatio

lina2011 [118]

Answer:

The point of intersection is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

$y=0.5x+5$

Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is (0, 5), h = 0 and k = 5. The radius is 3. So, r = 3. Substitute:

$(x-0)^2+(y-5)^2=(3)^2$

Simplify:

$x^2+(y-5)^2=9$

At the point where the two equations intersect, its x-coordinate and y-coordinate will be the same. Therefore, we can substitute the equation of the line into the equation of the circle and solve for x. So:

$x^2+((0.5x+5)-5)^2=9$

Simplify:

$x^2+(0.5x)^2=9$

Square:

$x^2+0.25x^2=9$

Combine like terms:

$\displaystyle 1.25x^2=\frac{5}{4}x^2=9$

Solve for x:

$\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}$

Note that since we are looking for the point of intersection in QI, x should be positive. So, we can ignore the negative answer.

To find the y-coordinate, substitute the x-value back into either equation. Using the linear equation:

$\displaystyle y=0.5\left(\frac{6\sqrt{5}}{5}\right)+5=\frac{3\sqrt{5}}{5}+5\approx 6.34$

So, the point of intersection in QI is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

6 0

2 years ago

Generic sugar which costs $2.23/kg is made by combining brand X sugar which costs $1.18/kg with brand Y sugar which costs $3.98/

White raven [17]

Answer:

X = 14 kg

Y= 7 kg

Step-by-step explanation:

LET X and Y equal the amounts of brand X and Y

X = kg of brand X

Y = kg of brand Y

we know:

1) X + Y = 21 (kg)

2) 1X + 4Y = 2(X + Y) (This is the cost/kg * amounts for total cost)

Coefficients 1,4,2 are the cost/kg)

substitute eq. 1 (X+Y), = 21 into right side of equation 2

1X + 4Y = (21)*2

use elimination to solve 2 equations

X + Y = 21

X + 4Y = 42 (now subtract, note: I wrote the 1X as just X)

------------------

0 -3Y = -21 OR Y = 7 kg so X = (21-7) OR X = 14 kg

5 0

2 years ago