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Licemer1 [7]
2 years ago
11

What is the solution to this system of linear equations?

Mathematics
2 answers:
Butoxors [25]2 years ago
5 0

Answer: (7, 3)

Step-by-step explanation:

x - 3y = -2

x + 3y = 16

Here we can add the two equations together to cancel out the y

2x = 14

divide by 2 on both sides to get

x = 7

Now that we have the X value, plug in x value into an equation to get the Y

x - 3y = -2

7 - 3y = -2

-3y = -9

y = 3

So the solution is (7, 3)

Readme [11.4K]2 years ago
3 0

Answer:

(7,3)

Step-by-step explanation:

you can add the equations together to eliminate y and first solve for x

(x-3y = -2) + (x+3y=16) = (2x = 14)

x = 7

then plug x into one of the equations to solve for y

(7) - 3y = -2

9 = 3y

y = 3

the solution is (7,3)

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Which is it? please help me and i will give brainliest
Cerrena [4.2K]

Answer: A, 1/2

Step-by-step explanation:

he is simply using 1 cup of bs for each cup of ws so when you do it its i cup of ws then its hald of 1 bs

3 0
3 years ago
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Find the midpoint of the segment whose endpoints are (-6,-8) and (3,6) show your work!
pogonyaev

Answer:

-1.5, -1

Step-by-step explanation:

midpoint formula

(x1 + x2 / 2) , (y1 + y2/ 2)

-6 + 3 / 2 ,   -8  + 6 / 2

3 0
3 years ago
Read 2 more answers
27
katrin2010 [14]

Answer:

A  ≈ 35.3 units²

Step-by-step explanation:

Calculate the radius CB using Pythagoras' identity in the right triangle.

CB² + AB² = AC²

CB² + 6² = 9²

CB² + 36 = 81 ( subtract 36 from both sides )

CB²  = 45 = r²

Then area of quarter circle is

A = \frac{1}{4} × πr² = \frac{1}{4} × π × 45 ≈ 35.3

6 0
3 years ago
How do I graph this linear equation y=3x+4
Talja [164]
First mark a point at 4 on the y axis
Then because the slope is 3 you are going to rise three places up and one place to the right.
Use a ruler to connect the dots.
Hope this helps.
5 0
3 years ago
Please help. Thank you!
katrin2010 [14]

Answer:

3a. ⇒ 2700 cm³

3b. ⇒ 72,900 cm³

3c. ⇒ 27

Step-by-step explanation:

3a.

∵ The model in a shape of square pyramid

∴ Its volume = base area × height

∵ Base shaped square with side length 15 cm

∴ Area of base = 15 × 15 = 225 cm²

∵ The model height = 12 cm

∴ She needs = 225 × 12 = 2,700 cm³ of plaster

3b.

∵ Each dimension in the actual stage = 3 times the model

∴ The side of the square base = 15 × 3 = 45 cm

∴ The height = 12 × 3 = 36 cm

∴ The area of the base = 45 × 45 = 2,025 cm²

∴ She needs = 2025 × 36 = 72,900 cm³ of plaster

3c.

∵ Each length in the actual stage is 3 times the model

∴ The volume of the actual stage = (3)³ the volume of the model

∴ The volume of the actual stage = 27 the volume of the model

<em>To check your answer:</em>

Volume actual ÷ Volume model = 72,900 ÷ 2700 = 27

3 0
3 years ago
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