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1 year ago

What is the solution to this system of linear equations?

Mathematics

2 answers:

Butoxors [25]1 year ago

5 0

Answer: (7, 3)

Step-by-step explanation:

x - 3y = -2

x + 3y = 16

Here we can add the two equations together to cancel out the y

2x = 14

divide by 2 on both sides to get

x = 7

Now that we have the X value, plug in x value into an equation to get the Y

x - 3y = -2

7 - 3y = -2

-3y = -9

y = 3

So the solution is (7, 3)

Readme [11.4K]1 year ago

3 0

Answer:

(7,3)

Step-by-step explanation:

you can add the equations together to eliminate y and first solve for x

(x-3y = -2) + (x+3y=16) = (2x = 14)

x = 7

then plug x into one of the equations to solve for y

(7) - 3y = -2

9 = 3y

y = 3

the solution is (7,3)

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2 years ago

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Tcecarenko [31]

Answer:

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2 years ago

Which two values of x are roots of the polynomial below?

Julli [10]

Answer:

B. and C.

Step-by-step explanation:

1. Set the polynomial equal to zero:

x² + 5x + 7 = 0

2. Plug the given values of a, b, and c into the quadratic formula:

$x=\frac{-5+-\sqrt{5^{2}-4(1)(7) } }{2(1)}$

3. Solve the square root:

$x=\frac{-5+-\sqrt{25-4(1)(7)} }{2(1)}$

$x=\frac{-5+-\sqrt{25-28} }{2(1)}$

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4. Simplify the rest:

$x=\frac{-5+-\sqrt{-3} }{2}$

5. Separate the solutions:

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Thus, options B and C are the answers.

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2 years ago

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FrozenT [24]

Answer:

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2 years ago

Read 2 more answers

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(B)
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(C)
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2 years ago