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miss Akunina [59]
3 years ago
11

Write the equation of a line in point-slope form that goes through the coordinate

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

hope this helps you

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V=2.5(6.4−t)
Alja [10]

Answer:

6.4 minutes ( or 6 minutes and 24 seconds)


Step-by-step explanation:

Filling up the jug means the empty space is 0, hence V = 0.

<em>We plug in 0 into V and solve for t to get the time required to fill it up:</em>

V=2.5(6.4-t)\\0=2.5(6.4-t)\\0=16-2.5t\\2.5t=16\\t=\frac{16}{2.5}\\t=6.4


Hence it will take 6.4 minutes to fill up the jugs.

<u>Note:</u> 0.4 minutes in seconds is  0.4*60=24 seconds

6 0
3 years ago
What is 2x-y=6 the slope
Flura [38]

First of all, lets get y on its own side of the equation.

-y=-2x+6\\y=2x-6\\

This is slope intercept form, y=mx+b, where m is slope.

we can see that m=2, so the slope is 2 or \frac{2}{1}

5 0
3 years ago
Read 2 more answers
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
Talia gave her hairdresser a 20 percent tip, which amounted to $7. What was the price of the service before the tip?
mina [271]
I don't know if I did it right but here's my guess. I think you multiply 7 by 20% and that gives you 1.40 as a result. Compared to the other method I used (division), I'm pretty sure I'm right since the other result was 35. Doesn't make sense if the end amount was $7.
4 0
3 years ago
Read 2 more answers
a rectangular plot of land 8m long and 6m wide.there is a flower bed in the form of a circle of radius 3m.find 1.area of land. 2
mixer [17]

Answer:

1)Area of the Land  is 48 square meters

2) Area of flower bed   is  28.26 square meter

3)Area of land excluding flower bed   is 19.74 square meters

4)cost of planting grass in land  excluding flower bed   is Rs 118.44

Step-by-step explanation:

Given:

Length of the Rectangular plot = 8m

Width of the rectangular plot =  6m

Radius of the circular flower bed = 3m

1)Area of the Land  

Area of the Rectangular plot  = Area of the Land  

Area of the Land   = length x width

Area of the Land   =  8*6

Area of the Land  = 48 square meters-----------------------------(1)

2. Area of flower bed

Area of flower bed =  4 x area of one quadrant

Area of flower bed =  area of the circle

Area of flower bed  = \pi r^2

where r is the radius

Now , substituting the values

Area of flower bed = \pi (3)(3)

Area of flower bed = 28.26 square meters-----------------------------(2)

3)Area of land excluding flower bed

Area of land excluding flower bed =  Area of the rectangular land - area of flower beds

Area of land excluding flower bed =  48 - 28.26

Area of land excluding flower bed = 19.74 square meters

4)cost of planting grass in land

Cost of planting grass per square meter = 6

Excluding the flower bed we have  19.74 square meters. to plant grass  for this 19. 74 square meters, the cost will be

=19. 74 \times 6

= Rs 118.44

6 0
3 years ago
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