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olga nikolaevna [1]
2 years ago
7

A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second

column is labeled f of x with entries 18, 3, 0, 3, 6, 3.
Using only the values given in the table for the function f(x) = –x3 + 4x + 3, what is the largest interval of x-values where the function is increasing?

(
,
)
Mathematics
1 answer:
ikadub [295]2 years ago
7 0

The largest interval of x-values where the function is increasing is (-1, 1)

<h3>How to determine the largest increasing interval?</h3>

The table of values is added as an attachment

From the table, the function f(x) decreases from x = -3 to x = -1 and x = 1 and x = 2

So, we make use of the intervals

x = -1, 0 and 1

From the table,

From x = -1 to 0, the change is 3

From x =  0 to 1, the change is 3

From x =  -1 to 1, the change is 6

Using the above highlights, the largest increasing interval is (-1, 1)

Hence, the largest interval of x-values where the function is increasing is (-1, 1)

Read more about function interval at:

brainly.com/question/1399055

#SPJ1

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4. (03.03 HC)
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A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

               look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

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relation : f(x) = 8x - 5....when x = 8

             f(8) = 8(8) - 5

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             f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

    19 = 8x - 5

     19 + 5 = 8x

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7 0
3 years ago
Given the points A and BThe coordinates of point A = ( 3 , 1 )The coordinates of point B = (-1 , -1)The midpoint of AB = ([?],[
mr Goodwill [35]

Given the points A and B

The coordinates of point A = ( 3 , 1 )

The coordinates of point B = (-1 , -1)

The midpoint of AB, is the point C

C will be calculated as following :

C=\frac{A+B}{2}=\frac{(3,1)+(-1,-1)}{2}=\frac{(3-1,1-1)}{2}=\frac{(2,0)}{2}=(1,0)

so, the midpoint of AB = (1 , 0 )

3 0
1 year ago
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