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Ksenya-84 [330]
3 years ago
13

After Ricardo received his allowance for the week, he went to the mall with some friends. He spent half of his allowance on a ne

w paperback book. Then he bought himself a snack for $1.25. When he arrived home, he had $5.00 left. How much was his allowance?
Mathematics
2 answers:
ad-work [718]3 years ago
6 0
Lets work backwards, he had $5 after it all, and spent $1.25 on a snack, so we add that to the remainder, which is $6.25. then he spent half of that on whatever stuff he likes, so add $6.25 and $6.25, which is $12.50
DerKrebs [107]3 years ago
3 0

Answer:

$12.50

Step-by-step explanation:

We have to find value of his allowance

Let Ricardo received allowance =x

He spent his allowance on anew paperback book=\frac{x}{2}

He spent money on snacks=$1.25

He had money left=$5.00

According to question

\frac{x}{2}+1.25+5=x

6.25=x-\frac{x}{2}

6.25=\frac{2x-x}{2}

\frac{x}{2}=6.25

x=6.25\times 2

x=12.50

Hence, Ricardo received his allowance for the week =$12.50

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135 cm

Step-by-step explanation:

Let Jose's height = x

The mean of their heights = 150

Given the Heights:

150cm, 170cm, 140cm, 155cm

The mean is the sum if the heights divided by the number of people

Here :

(150 + 170 + 140 + 155 + x) / 5 = 150

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615 + x = 750

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A = 2lw + 2lh + 2wh
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The bacteria in an old piece of cheese is growing at a rate that can be modeled by y = 280 • 2^x. Determine which number represe
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In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
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Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
4 years ago
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