Question

Geometric series 2 + 6 + 18 + 54 + ... , find tn

Answer 1

The function that gives the value of tn for the geometric series is presented as follows;

$t_n = 2 \times 3^{(n - 1)}$

How can the expression that represents the geometric series be found?

The given geometric series is presented as follows;

2 + 6 + 18 + 54 +...

From the above series, we have;

• First term, a = 2

• Common ratio, r = 6 ÷ 2 = 18 ÷ 6 = 54 ÷ 18 = 3

The nth term of the geometric series is therefore;

$t_n = a \cdot r^{(n - 1)}$

Which gives;

$t_n = 2 \times 3^{(n - 1)}$

Where, tn is the nth term

Learn more about geometric series here:

brainly.com/question/2289626

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