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3 years ago

Evaluate for x = 2. (12x + 8) 4 A) 4 B) 5 C) 6 D) 8

1 answer:

3 0

What you want to do here is plug 2 in for x. when a question asks you to evaluate a certain equation at a certain number, it's just asking you to plug the value in for your variable. i'm assuming that 12x + 8 is meant to be set over 4 as a fraction.

(12(2) + 8)/4 ... figure out the top first. 12*2 = 24, 24 + 8 = 32.

32/4 = 8, so your correct choice is D.

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

Can someone help me with 13-16 I’ll mark brainliest please guys I’m begging

oee [108]

Answer:

you can look the first 3 up online
16. B

3 0

3 years ago

Read 2 more answers

He table shows the solution to the equation |2x − 5| − 2 = 3:

ozzi

The solution is completely correct, as putting 5 or 0 in the formula again will make it true.

$|2(0)-5|=5$
$|-5|=5$
$5=5$

$|2(5)-5|=5$
$|10-5|=5$
$5=5$

6 0

4 years ago

Select all that apply <br> thαnkѕ pєrѕσn

vodka [1.7K]

Im gonna guess and say the right ones might be
A = AB or A'B'
B = CB or C'B'
D = CA or C'A'
Cus all equal the same side
H0P3 It H2LPS :)
or something

8 0

3 years ago

Karen spends $450 on monthly bills. Of this total amount, 12% is for phone service, 1/10 is for internet service, and 2/9 is for

finlep [7]

12%= 0.12 = 12/100 = 108/900
1/10 = 90/900
2/9 = 200/900

108/900 + 90/900 + 200/900 = 398/900 used

900- 398 = 502

502/900 = 251/ 450

251/450 × 450 = 251

Karen has $251 for food

4 0

3 years ago