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2 years ago

M∠ __ +m∠BPD=180∘ what is the blank for Linear Pairs

Mathematics

1 answer:

Marianna [84]2 years ago

6 0

The blank space to form a linear pair with m∠BPD is m∠APD.

<h3>What are linear pair angles?</h3>

Linear pair of angles are formed when two lines intersect each other at a single point.

Linear pair angles are adjacent to each other.

Therefore, the sum of a linear pair angles is equals to 180 degrees.

This means linear pair angles are supplementary.

Hence,

m∠APD + m∠BPD = 180°

learn more on linear pair angles here: brainly.com/question/26555759

#SPJ1

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For the lines x=3t, y=1-2t, z=2-3t and x (3, 1, 4) +s(-9, 6, 9) (a) Show that the lines are parallel. (b) Calculate the distance

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Step-by-step explanation:

Given lines in parametric form

line $L_1$

$\frac{x}{3}=\frac{y-1}{-2} =\frac{z-2}{-3}$

direction vector of $L_1 v_1=$

Line $L_2$

direction vector of $L_2 v_2=$

therefore

$v_2=-3v_1$

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(ii)distance between two lines is

$L_2$ is given by

$\frac{x-3}{-9}=\frac{y-1}{6} =\frac{z-4}{9}$ =s

$\frac{x-3}{-3}=\frac{y-1}{2} =\frac{z-4}{3}$ =3s

$\left | \frac{\begin{vmatrix}x_2-x_1 &y_2-y_1 &z_2-z_1 \\ a_1&b_1&c_1 \\ a_2&b_2&c_2\end{vmatrix}}{\sqrt{\left ( a_1b_2-a_2b_1 \right )^2+\left ( b_1c_2-b_2c_1 \right )^2+\left ( c_1a_2-c_2a_1 \right )^2}}\right |$

where $a_1$ =3

$b_1$ =-2

$c_1$ =-3

$a_2$ =-9

$b_2$ =6

$c_2$ =9

distance(d)=0 units since value of the matrix

$\begin{vmatrix}x_2-x_1 &y_2-y_1 &z_2-z_1\\ a_1&b_1&c_1 \\a_2&b_2 &c_2 \end{vmatrix}$

is zero

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