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UNO [17]
3 years ago
13

In 5 OR MORE SENTENCES, write a short story explaining the graph OR write about the key features of the graph.

Mathematics
1 answer:
rewona [7]3 years ago
6 0

The graph illustrated is divided into three seperate sections namely <em>A, B and C,</em> the short story culled from the graph is described thus:

Rate of change or slope = (Rise/ Run)

  • <em>Rise = y2 - y1 </em>
  • <em>Run = x2 - x1 </em>

<u>SECTION A:</u><u> </u>

Slope = (40 - 0) ÷ (20 - 0) = 40/20 = 2

Distance traveled = 50 meters

<u>SECTION B</u> :

This section gives an horizontal line, hence, the slope is 0.

Distance covered = 0 ; as there was no change in the distance over the period of time.

<u>SECTION</u><u> </u><u>C</u><u>:</u>

Slope = (80 - 50) ÷ (70 - 60) = 30/10 = 3

The total distance traveled = 80 - 50 = 30 meters

<u>The total </u><u>distance</u><u> </u><u>and</u><u> </u><u>time spent traveling</u> :

Total distance traveled = (50 + 30) = 80 meters

Total time spent = 70 seconds (<em>time at the 80 meter mark</em>)

Hence, the story.

Learn more : brainly.com/question/25309609

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The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.
Wittaler [7]

<span>First we calculate z using the formula:

z = (x - μ)/σ</span>

Where:

x = our variable, 10

μ = mean, 8

σ = standard dev, 2

Substituting known values:<span>
z = (10 - 8)/2
z = 2/2
z = 1

Using the tables of the normal distribution to find the p-value with z = 1

p = 0.8413

Since we want "greater than 10”, we need to subtract the probability from 1 therefore

p* = 1 - 0.8413 = <span>0.1587</span></span>

6 0
3 years ago
What is the surface area of a cylinder with base radius 4 and height 5?
seropon [69]

Answer:

Solution given:

radius [r]=4

height [h]=5

we have

Surface area of cylinder=2πr(r+h)

=2π×4(4+5)

=<u>72πunits³ is a required volume.</u>

7 0
2 years ago
The bottom portion of a loading bin is cone shaped. The base radius of this part of the bin is 3.5 feet and the slant height is
jek_recluse [69]

\bf \textit{lateral surface of a cone}\\\\ LA=\pi r\sqrt{r^2+h^2}~~ \begin{cases} ~~ r=radius\\ sh=\stackrel{slant~height}{\sqrt{r^2+h^2}}\\[-0.5em] \hrulefill\\ r=3.5\\ sh=6.5 \end{cases}\\\\\\ LA=\pi (3.5)(6.5)\implies LA\approx71.47 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{sh}{6.5}=\sqrt{r^2+h^2}\implies 6.5=\sqrt{3.5^2+h^2}\implies 6.5^2=3.5^2+h^2 \\\\\\ 6.5^2-3.5^2=h^2\implies \sqrt{6.5^2-3.5^2}=h\implies \sqrt{30}=h \\\\[-0.35em] ~\dotfill

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3.5\\ h=\sqrt{30} \end{cases}\implies V=\cfrac{\pi (3.5)^2\sqrt{30}}{3}\implies V\approx 70.26

7 0
3 years ago
Read 2 more answers
Please help i am stuck
balu736 [363]

Explanation:

All of these are done the same way.

1. Set your compass to a distance slightly longer than the distance from the point to the line you want the perpendicular to.

2. Using the point as a center, draw an arc that intersects the line in 2 places. Consider those points to be "P" and "Q".

3. You can leave the compass as is, or set it to any other distance longer than half the distance between P and Q. Using this radius, and using P and Q as centers, draw intersecting arcs on the other side of the line from the original point. Consider the intersection of those arcs to be point "R".

4. A line through the original point and point R will be perpendicular to the line, as you want.

_____

In problem 1, the point and line are obvious.

In problem 2, the point is the vertex opposite the line of interest. (There will be 3 similar constructions.)

6 0
2 years ago
-3(x + 2)2 + 4 = -8<br> what’s the answer
podryga [215]
X=0

-3(0+2)2+4 distribute -3 to the parentheses-PEMDAS
(0-6)2+4 multiply 2 by the parentheses
(0-12)+4 solve the equation
= -8
8 0
3 years ago
Read 2 more answers
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