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3 years ago

In 5 OR MORE SENTENCES, write a short story explaining the graph OR write about the key features of the graph.

1 answer:

6 0

The graph illustrated is divided into three seperate sections namely A, B and C, the short story culled from the graph is described thus:

Rate of change or slope = (Rise/ Run)

Rise = y2 - y1
Run = x2 - x1

SECTION A:

Slope = (40 - 0) ÷ (20 - 0) = 40/20 = 2

Distance traveled = 50 meters

SECTION B :

This section gives an horizontal line, hence, the slope is 0.

Distance covered = 0 ; as there was no change in the distance over the period of time.

SECTION C:

Slope = (80 - 50) ÷ (70 - 60) = 30/10 = 3

The total distance traveled = 80 - 50 = 30 meters

The total distance and time spent traveling :

Total distance traveled = (50 + 30) = 80 meters

Total time spent = 70 seconds (time at the 80 meter mark)

Hence, the story.

Learn more : brainly.com/question/25309609

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In the figure, AB∥CD. Find x and y.

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Answer:

y=131°

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Step-by-step explanation:

∠ ABD and ∠ BDC are supplementary.

The sum of the supplementary angles =180 °

thus y-4+x=180...........i

x and 37° are complementary, that is, they add up to 90°

Thus, x=90-37=53°

Using this value in equation 1 we obtain:

y-4°+53° =180°

y= 180°-53°+4°

y=131°

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3 years ago

What 6 divided by 108 long divison

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The commuting time for a student to travel from home to a college campus is normally distributed with a mean of 30 minutes and a

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Answer:

0.1587

Step-by-step explanation:

Let X be the commuting time for the student. We know that $X\sim N(30, (5)^2)$ . Then, the normal probability density function for the random variable X is given by

$f(x) = \frac{1}{\sqrt{2\pi(5)^{2}}}\exp[-\frac{(x-\mu)^{2}}{2(5)^{2}}]$ . We are seeking the probability P(X>35) because the student leaves home at 8:25 A.M., we want to know the probability that the student will arrive at the college campus later than 9 A.M. and between 8:25 A.M. and 9 A.M. there are 35 minutes of difference. So,

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4 years ago

Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,

scoundrel [369]

Answer: $\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

$23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes$

You know that he had 30 minutes in time-out, he counted spots on the ceiling for $\frac{70}{3}$ minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and $\frac{70}{3}$ minutes:

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3 years ago

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