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2 years ago

For 10-18, Determine whether the triangles can be proved

Mathematics

1 answer:

navik [9.2K]2 years ago

3 0

Answer:

180 - 92 - 41 = 47

There are not two similar congruent angle in the triangles.

Hope this helps!

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Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!

Ilya [14]

Answer:

$\boxed{\sf sin\ C =\frac{40}{41}}$

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}$

Substitute the respective values ,

$\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}$

<u>Hence the required answer is 40/41.</u>

6 0

3 years ago

Which one is it A B C D

vovangra [49]

Answer:B

Step-by-step explanation: Alternate exterior angles theorem

3 0

3 years ago

If f(x) = x2 − 2x + 9 and g(x) = 8 − x, what is (f o g)(−4)?

erastovalidia [21]

I hope this helps you

3 0

3 years ago

Please help !! Will mark brainliest answer

Norma-Jean [14]

Answer:

x = 12

Step-by-step explanation:

18:24 (comparing the same sides for the similar shapes; 18 and 24) when simplified down is equal to 3:4.

Using this 3:4 scale factor we can find the missing side x.

Solving for x :

$\frac{3}{4}$ × 16 = 12

x = 12

OR: Set up a proportion:

$\frac{24}{16}$ × $\frac{18}{x}$

<em>cross-multiply</em>

16 × 18 = 288

24 × x = 24x

288 = 24x

x = 12

3 0

3 years ago

Some college graduates employed full-time work more than hours per week, and some work fewer than hours per week. We suspect tha

Alex_Xolod [135]

Answer:

a)Null hypothesis: $\mu =40$

Alternative hypothesis: $\mu \neq 40$

b) A Type of error I is reject the hypothesis that $\mu$ is equal to 40 when is fact $\mu is equal to 40c) We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"Step-by-step explanation:Assuming this problem: "Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, [tex]\mu$ , is different from 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 43 hours and that the standard deviation is 4 hours. Based on this information, answer the questions below"

Data given

$\bar X=43$ represent the sample mean

$\mu$ population mean (variable of interest)

s=4 represent the sample standard deviation

n represent the sample size

Part a: System of hypothesis

We need to conduct a hypothesis in order to determine if actual mean is different from 40 , the system of hypothesis would be:

Null hypothesis: $\mu =40$

Alternative hypothesis: $\mu \neq 40$

Part b

In th context of this tes, what is a Type I error?

A Type of error I is reject the hypothesis that $\mu$ is equal to 40 when is fact [tex]\mu is equal to 40

Part c

Suppose that we decide not to reject the null hypothesis. What sort of error might we be making.

We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"

5 0

3 years ago

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