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3 years ago

12

The following data shows the changes in tempreatures across varius cities from moorning to noon. which city recorded the maximum

tempreature
20
12
13
25

1 answer:

fgiga [73]3 years ago

6 0

25 because it is cool and it is the maximum weather in the earth totally

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Jerry bought toy trains at the store. He gave 15 away and had 9 left. Which of the following shows how

Paladinen [302]

The answer of this question is<u> 24 toy trains.</u>

<u>Step-by-step explanation:</u>

Given,

Jerry gave away 15 trains .

Jerry left with 9 trains .

Jerry total brought toy trains = given away toy trains + left with toy trains

Total toy trains = 15 + 9

Total toy trains = 24

<u>Jerry brought a total of 24 toy trains.</u>

7 0

3 years ago

If the total number of people attending the game was 64,000, how many people were

guapka [62]

Is this the whole question ?

6 0

2 years ago

(hg^(-3))/(w^(-4) k^0 )

Svetlanka [38]

One may note you never quite asked anything, now, assuming simplification,

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{hg^{-3}}{w^{-4}k^0}\implies \cfrac{hw^4}{g^3(1)}\implies \cfrac{hw^4}{g^3}$

4 0

2 years ago

Two bicycle wheels are shown below which is closest to the circumference in inches of the larger wheel.

olganol [36]

We estimate the diameter of the larger wheel to be 24 to 25 inches.

The formula for the Circ. of a circle in terms of the diameter is C = pi*d.

Here, the Circ. of the larger wheel is approx C = pi(24 inches) = 24*pi inches,
or

24(3.14) inches = 75.36 inches. You must now choose from the four answer choices. Which one is closes to 75.36 inches?

7 0

2 years ago

A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of

Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

$m=\frac{y2-y1}{x2-x1}$

$m=2$

so

$2=\frac{y2-y1}{x2-x1}$ -----> equation A

$x2=x1+3.5$ ----> equation B

substitute equation B in equation A

$2=\frac{y2-y1}{x1+3.5-x1}$

$2=\frac{y2-y1}{3.5}$

$7=y2-y1$

$y2=y1+7$

therefore

The ordinate of B exceeds the ordinate of A by 7

6 0

2 years ago