Complete question :
The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Answer:
-6°F
Step-by-step explanation:
Temperature at 5am (t1) = - 6°F
Temperature at 3pm (t2) = 36°F
Change in temperature, between 5am and 3pm:
(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F
Hence, temperature at 8:00 pm:
High temperature - change in temperature between (5am - 3pm)
36°F - 42°F = - 6°F
Answer:
Step-by-step explanation:
Try and become familiar with a program like Desmos. It will do wonderful things for you.
I have graphed
Red: y = -2x + 5 (The 5 is the y intercept. For this question it could be anything.
Blue: y = - 4x + 5 Same note as above.
Answer:
Discount = $30, Final price = $90
Step-by-step explanation:
25% is one quarter. 120/4=30
One quarter of 120 is 30, so - 30 would give discounted price of $90.
Similarly you could think of it like the discounted price is 75% of the original one and do 120x0.75=90 to find 75% of 120.
Hope this helped!
Answer: 7) 50.27 8) 251.33 9) 235.62 *These answers were calculated using the true value of pi, not 3.14*
