Answer:
30
Step-by-step explanation:
1.Substitute the x for 12.
2.Multiply the 2 by 12.
3.Then add 6 to your answer.
The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :


We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
brainly.com/question/10633821
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Answer:1/9
Step-by-step explanation:
Simplified:
1/3 x 1/3
1/9
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I think the correct answer is B. It is the triangle case SSA that may have one, two, or zero solutions. This case can have either number of solutions but it depends on the sides of the triangle given. Having one solution can be all of the cases except SSS, having 2 solutions can only be applied to SSA.