Answer:
no of child tickets sold were 58
Step-by-step explanation:
Let the number of child ticket sold be x
cost of 1 child ticket = $6.10
Total cost of x child ticket = x*cost of 1 child ticket = = $6.10x
Let the number of adult ticket sold be y
cost of 1 adult ticket = $9.90
Total cost of y adult ticket = y*cost of 1 adult ticket = = $9.90y
Given total ticket sold = 142
Thus,
number of child ticket sold + number of adult ticket sold = 142
x + y = 142 - equation 1
x = 142 -y
Total sales of ticket = $1185.40
total sales of ticket = Total cost of x child ticket + Total cost of x a dult ticket
6.10x + 9.90y = 1185.40
in this equation substituting x = 142 - y from equation 1
6.10(142 - y ) + 9.90y = 1185.40
=>866.2 - 6.10y + 9.90y = 1185.40
=> 3.80y = 1185.40 - 866.2
=> 3.80y = 319.2
=> y = 319.2/3.80 = 84
Thus, y = 84
x = 142 - y = 142 - 84 = 58
Thus, no of child tickets sold were 58
