The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ = 
σ = 5.398
Z = X-ц / σ
Z = 
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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Answer:
d
Step-by-step explanation:
Answer:
4x + 3y = 5
Step-by-step explanation:
Gradient = -9 -11/ 8 + 7
= -4/3
Equation of the line...
y = mx + c
y = -4/3(x + 7) + 11
Multiplying through by 3...
3y = -4x - 28 + 33
3y = -4x + 5
4x + 3y = 5
Answer:

Step-by-step explanation:
It is known that,
<em>'Vertical stretch, stretches the function up and down towards the y-axis'.</em>
The general form of vertical stretch is given by 'kf(x)', where k>1 is the factor by which function is stretched.
As, we have the function
which is stretched by a factor of 4.
Thus, the new function will be
.
Hence, the equation for the vertical stretch is
.
Answer:
im sorry cant help
Step-by-step explanation: