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lara31 [8.8K]
2 years ago
11

Evaluate 2x for each value of x. Write your answers in simplest form. Show your work!

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
6 0

1. 1/2

2.2/3

3. 1

4. 1/3

5. 2/7

6. 1/4

7. 4/3

8. 3/2

<h3>How to evaluate the value</h3>

To find 2x of the vale of x, we have to multiply the value of 'x' by 2

1. x = 1/4

2x = 2 * \frac{1}{4} ⇒ \frac{2}{4} ⇒\frac{1}{2}

2. x = 1/3

2x = 2 * \frac{1}{3} ⇒\frac{2}{3}

3. x = 1/2

2x = 2* \frac{1}{2} ⇒ \frac{2}{2} ⇒ 1

4. x= 1/6

2x = 2* \frac{1}{6} ⇒ \frac{2}{6} ⇒ \frac{1}{3}

5. x = 1/ 7

2x = 2 * \frac{1}{7} ⇒ \frac{2}{7}

6. x = 1/8

2x = 2 * \frac{1}{8} ⇒ \frac{2}{8} ⇒ \frac{1}{4}

7. x = 2/3

2x = 2 * \frac{2}{3} ⇒ \frac{4}{3}

8. x = 3/4

2x = 2 * \frac{3}{4} ⇒ \frac{6}{4} ⇒ \frac{3}{2}

Learn more about algebraic expressions here:

brainly.com/question/723406

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Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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Answer:

5 terms:  m, 4, 2, -7m, 6 are the terms in question.

Step-by-step explanation:

Note that terms here are separated from one another by either + or - signs.

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2 - 7m are separated by the - operator, and so there are two terms here.

Completing the counting procedure, we get:

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So, if we do NOT combine like terms, we have five (5) terms altogether.

If we DO combine like terms, we end up with two (2) terms:

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Answer:

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