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3 years ago

How many possible bends could this graph have?

Mathematics

2 answers:

Licemer1 [7]3 years ago

8 0

It could have 2 or 4 real roots

so 1 bend or 3

bazaltina [42]3 years ago

4 0

It can have any amount just depending on the equation so it wil be a) because it depends on the equation

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What binomial do you have to add to the polynomial 2x^2+3y^2-5xy+1 to get the following?

Contact [7]

Binomial $-3y^{2}+5xy$ when added to polynomial $2x^{2} +3y^{2} -5xy+1$ gives polynomial that does not contain the variable y .

<h3>What is binomial?</h3>

A mathematical expression consisting of two terms connected by a plus sign or minus sign .

Example: x + 2 is a binomial, where x and 2 are two separate terms.

<h3>What is polynomial?</h3>

A polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer

According to the question

polynomial $2x^{2} +3y^{2} -5xy+1$

when added with $-3y^{2}+5xy$

= $2x^{2}+1$ (as $3y^{2} -5xy$ got cancelled )

that does not contain the variable y

Hence, Binomial $-3y^{2}+5xy$ when added to polynomial $2x^{2} +3y^{2} -5xy+1$ gives that does not contain the variable y .

To know more about Binomial and polynomial here :

brainly.com/question/1698358

# SPJ2

3 0

2 years ago

Read 2 more answers

Which equation represents a line that passes through (2,-1/2) and has a slope of 3 ?

Anna11 [10]

Answer:

C. $y + \frac{1}{2} = 3(x - 2)$

Step-by-step explanation:

Given

$Point: (2,\frac{-1}{2})$

$Slope: 3$

Required

Equation of line

Let m represents the slope of the line;

m is calculated as thus

$m = \frac{y - y_1}{x - x_1}$

$where (x_1,y_1) = (2,\frac{-1}{2})$

$So; x_1 = 2; y_1 = \frac{-1}{2}$

$m = 3$

By substituting the right values in the formula above;

$m = \frac{y - y_1}{x - x_1}$ becomes

$3 = \frac{y - \frac{-1}{2}}{x - 2}$

Multiply both sides by $(x - 2)$

$3 *(x - 2) = \frac{y - \frac{-1}{2}}{x - 2} *(x - 2)$

$3 *(x - 2) = (y - \frac{-1}{2})$

$3 *(x - 2) = (y + \frac{1}{2})$

$3(x - 2) = (y + \frac{1}{2})$

$3(x - 2) = y + \frac{1}{2}$

Reorder

$y + \frac{1}{2} = 3(x - 2)$

Hence, the equation that represents the line is $y + \frac{1}{2} = 3(x - 2)$

4 0

3 years ago

Which angles are adjacent to 8 ? select all that apply

Alinara [238K]

Answer:

I think 5 and 7 I got that question

3 0

2 years ago

Read 2 more answers

Perform the indicated row operation:

alexandr1967 [171]

Answer:

answers down below

Step-by-step explanation:

lol i hope it's this one

5 0

2 years ago

Read 2 more answers

Write a polynomial function, p(x) with degree 3 that has p(7)=0

MArishka [77]

Answer:

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

$(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}$

Take a = x

b = 7

Substitute in the identity we get

$(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343$

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

$p (x) = x^{3} - 21x^{2}+ 147x - 343$

4 0

3 years ago