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zmey [24]
3 years ago
7

Which equation has infinitely many solutions?

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0

Answer:

<h2>5(2x + 4) = 10(x + 2)</h2>

Step-by-step explanation:

An equation has infinitely many solutions when they end in 0 = 0, that is, both sides are exactly equivalent. In this case, basically, all real numbers are solution, it's like a line under the same line, it's like the reflexive property, every number is equal to itself.

The expression that fulfil that definition is the second one, because:

<h3>5(2x + 4) = 10(x + 2)</h3><h3>10x + 20 = 10x + 20</h3><h3>10x - 10x = 20 - 20x</h3><h3>0 = 0</h3>

Therefore, it's demonstrated that the second equation has infinite solutions, that is, all numbers are solutions.

luda_lava [24]3 years ago
3 0

Answer:

the answer is B

Step-by-step explanation:

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(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1

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