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3 years ago

7

Which equation has infinitely many solutions?

2 answers:

kvv77 [185]3 years ago

7 0

Answer:

<h2>5(2x + 4) = 10(x + 2)</h2>

Step-by-step explanation:

An equation has infinitely many solutions when they end in 0 = 0, that is, both sides are exactly equivalent. In this case, basically, all real numbers are solution, it's like a line under the same line, it's like the reflexive property, every number is equal to itself.

The expression that fulfil that definition is the second one, because:

<h3>5(2x + 4) = 10(x + 2)</h3><h3>10x + 20 = 10x + 20</h3><h3>10x - 10x = 20 - 20x</h3><h3>0 = 0</h3>

Therefore, it's demonstrated that the second equation has infinite solutions, that is, all numbers are solutions.

luda_lava [24]3 years ago

3 0

Answer:

the answer is B

Step-by-step explanation:

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Helppppppp pleaseeeeeee

pshichka [43]

Answer:

(2a, 2b)

Step-by-step explanation:

(0, 2b)

(2a, 0)

(2a, 2b)

I racked my brain for that.

4 0

3 years ago

Lauren Rob need to find a decimal equivalent to 39/50 Laura said she could write an equivalent fraction with 100 as the denomina

Lina20 [59]

Answer:

Laura and Rob are correct

Step-by-step explanation:

we have

39/50

1) Rob said he could divide the numerator by the denominator

so

using a calculator

39/50=0.78

Rob is correct

2) Laura said she could write an equivalent fraction with 100 as the denominator to converted into a decimal

so

Multiply by 2/2

(39/50)*(2/2)=78/100=0.78

Laura is correct

therefore

Laura and Rob are correct

5 0

3 years ago

Write the first five terms of the sequence defined by the explicit formula

denis-greek [22]

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

$a_n=21-2n^2$

So to find the first five terms of this sequence, we will substitute the values of $n$ (num here in the given formula:

$a_1=21-2(1)^2\\\\a_1=19$

$a_2=21-2(2)^2\\\\a_2=13$

$a_3=21-2(3)^2\\\\a_3=3$

$a_4=21-2(4)^2\\\\a_4=-11$

$a_5=21-2(5)^2\\\\a_5=-29$

Therefore, the first five terms of the sequence defined by the explicit formula $a_n=21-2n^2$ are 19, 13, 3, -11, -29.

5 0

3 years ago

Read 2 more answers

8x - 2 = -9 + 7x what does x equal

Nimfa-mama [501]

Answer:

x = - 7

Step-by-step explanation:

8x - 2 = -9 + 7x (add 2 to both sides)

8x - 2 + 2 = -9 + 7x + 2

8x = 7x - 7 (subtract 7x from both sides)

8x - 7x = 7x - 7 - 7x

x = - 7

4 0

3 years ago

Read 2 more answers

One pencil is 20 mm long and a second pencil is 4.2 cm long. How long would the total length of the pencils be in cm? (1 cm = 10

lubasha [3.4K]

Answer:

6.2 cm

Step-by-step explanation:

3 0

2 years ago