All categories

3 years ago

Which equation has infinitely many solutions?

Mathematics

2 answers:

kvv77 [185]3 years ago

7 0

Answer:

Step-by-step explanation:

An equation has infinitely many solutions when they end in 0 = 0, that is, both sides are exactly equivalent. In this case, basically, all real numbers are solution, it's like a line under the same line, it's like the reflexive property, every number is equal to itself.

The expression that fulfil that definition is the second one, because:

Therefore, it's demonstrated that the second equation has infinite solutions, that is, all numbers are solutions.

luda_lava [24]3 years ago

3 0

Answer:

the answer is B

Step-by-step explanation:

You might be interested in

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

$P(X=2) = \dfrac{3}{8}$

$P(\text{3 boys}) = \dfrac{1}{8}$

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

Favorable outcome: {GGB, GBG, BGG}

$P(X=2) =\dfrac{3}{8}$

d) probability that the couple have three boys.

Favorable outcome: {BBB}

$P(BBB) = \dfrac{1}{8}$

8 0

3 years ago

What is the slope of the graph?

Keith_Richards [23]

Use the coordinates of the two black dots:

(2,3) and (7,6)

Slope is the change in Y over the change in X:

Slope = (6-3) / (7-2)

Slope = 3/5

4 0

3 years ago

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

pav-90 [236]

Answer:

ans=13.59%

Step-by-step explanation:

The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean $\mu$ and standard deviation $\sigma$ , we have these following probabilities

$Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827$

$Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545$

$Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973$

In our problem, we have that:

The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months

So $\mu = 53, \sigma = 11$

So:

$Pr(53-11 \leq X \leq 53+11) = 0.6827$

$Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545$

$Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973$

-----------

$Pr(42 \leq X \leq 64) = 0.6827$

$Pr(31 \leq X \leq 75) = 0.9545$

$Pr(20 \leq X \leq 86) = 0.9973$

-----

What is the approximate percentage of cars that remain in service between 64 and 75 months?

Between 64 and 75 minutes is between one and two standard deviations above the mean.

We have $Pr(31 \leq X \leq 75) = 0.9545 = 0.9545$ subtracted by $Pr(42 \leq X \leq 64) = 0.6827$ is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.

To find just the percentage above the mean, we divide this value by 2

So:

$P = {0.9545 - 0.6827}{2} = 0.1359$

The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.

4 0

4 years ago

The volume inside a rectangle storage room is 2,079 cubic feet. The room is 3 feet high. Find the area of the floor?

Lelu [443]

The floor is 693 square feet

8 0

3 years ago

How to determine whether each relation is a function <br><br> {(3,-8),(-9,1),(3,2),(-4,1),(-11,-2)

crimeas [40]

No. notice you have (3,-8) and (3,2). a function cannot have the same number on the left of the come (the x value) with different values on the right (h the y values)

3 0

3 years ago