Answer:
Step-by-step explanation:
The discriminant is found in
which is part of the quadratic formula. In
, a = 4, b = 10, c = -16. Filling in for the discriminant:
It's positive so we know we have real roots; it's not a perfect square, so our solutions are 2 complex rational.
In 
, a = -16, b = -7, c = 3. Filling in for the discriminant:
It's positive and not a perfect square so the 2 solutions are complex rational
This is my answer! I solve it by myself, check it out!!!! Sorry for late
The total front footage of all three lots is 370.
We have been given the expression
We can rewrite the expression as 
In order to simplify the given expression, we can check if we have any common terms in the numerator and denominator.
We can write the term 72 which is in the numerator as 
Thus, the expression becomes
We can see that 4 is common in both numerator and denominator. Hence, we can cancel 4. Thus, we are left with
Therefore, we can rewrite the given expression as 54.
There is some ambiguity here which could be removed by using parentheses. I'm going to assume that you actually meant:
x-3
h(x) = ---------------
(x^3-36x)
To determine the domain of this function, factor the denominator:
x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)
The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.
Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."
Symbolically, the domain is (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).
