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1 year ago

Write a proportion for the statement. 40 is to 10 as 32 is to 8.

Mathematics

1 answer:

Svetach [21]1 year ago

6 0

Hi! ⋇

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All proportions have this form:

$\sf{\dfrac{a}{b}=\dfrac{c}{d}}$ , Where $\sf{\dfrac{a}{b}}$ is equal to $\sf{\dfrac{c}{d}}$ .

If $\sf{\dfrac{a}{b}\neq\dfrac{c}{d}}$ , it's not a proportion.

_________________________

Here we have two pairs of numbers:

40,10 and 32,8.

Written As a proportion, they look like :

$\sf{\dfrac{40}{10}=\dfrac{32}{8}}$

Hope this made sense to you :)

$\it{Calligrxphy}$

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You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

2 years ago

Suppose that a factory manufactures only tables and chairs and that the profit on one chair is $15 and on the table is $20. Each

Leya [2.2K]

Answer:

The data we have is:

Profit per chair = $15

Profit per table = $20

Chair needs: 1 large pice, 2 small pieces.

Table needs: 2 large pieces, 2 small pieces.

You have 6 large pieces and 8 small pieces, and you want to maximize the profit.

Let's define:

T = # of tables

C = # of chairs.

Total profit:

P = C*$15 + M*$20

The number of chairs that you can make is given by:

0 ≤ C ≤ 4

If you make 4 chairs, the profit is:

P = 4*$15 = $60

And there will be 2 large pieces left.

Now for the tables.

0 ≤ T ≤ 3

If you make 4 tables, the profit will be:

P = 3*$20 = $60 (same as before)

And there will be two small pieces left.

Then we want to use a medium number of tables and chairs, we can not use the maximum for any of those, the first thing we should try is:

we ideally would want to use all the pieces that we have.

8 small, 6 large:

Then we can make:

2 tables: we use 4 large pieces and 4 small pieces.

T = 2

And we have left 2 large pieces and 4 small pieces.

The leftover is enough to make two chairs.

C = 2.

In this case, where we used all our materials, the profit will be:

P = 2*$15 + 2*$20 = $30 + $40 = $70

The profit is maximized when we make 2 tables and two chairs.

5 0

3 years ago

A pair of parallel lines is cut by a transversal, as shown below.

MA_775_DIABLO [31]

Answer:

$x=45\degree$

Step-by-step explanation:

In the diagram, the measure of the $(x+30\degree)$ angle is equal to the $75\degree$ angle.

These two angles are alternate angles.

We therefore set up the following equation and solve for x.

$x+30\degree =75\degree$

$\Rightarrow x =75\degree-30\degree$

$\Rightarrow x =45\degree$

6 0

3 years ago

Read 2 more answers

What would the answer be???

Korolek [52]

Answer:

The solution is obtained by adding the two equations.

The solution is: (x, y) = ( $- \frac{2}{3}$ , $- \frac{7}{3}$ )

Step-by-step explanation:

We are given two equations with two variables. The strategy is to eliminate one variable and solve for both the variables.

The two equations are:

$7x + y = - 7 \hspace{15mm} \hdots (1)$

$2x - y = 1 \hspace{15mm} \hdots (2)$

Adding both the equations, we get:

$7x + 2x + y - y = - 7 + 1$

$\implies 9x = - 6$

$\implies x = - \frac{2}{3}$

Substituting the value of 'x', we get the value of y.

We substitute in (2). [Can be substituted in any equation].

We get: y = 2x - 1

$\imples y = 2\bigg(\frac{-2}{3}\bigg) - 1$

$\implies -\frac{4}{3} - 1$

$\implies y = -\frac{7}{3}$

So, we get the corresponding values of x and y which is the solution of the two equations.

4 0

2 years ago

Is 5.67 A)rational B)Irrational C)whole D) natural E)integer

Alexxx [7]

Rational it stops and repeats

5 0

2 years ago