<h3>
sin22° = 5/4</h3><h3>
tan22° = 3/√55</h3>
As we know that , sinA = opposite/hypotenuse & tanA = opposite/adjacent
So here we can find sin22° , because they already given the sides opposite & hypotenuse . And we can't find tann22° because they given the value of opposite but not given the value of adjacent side of the angle 22°
Now finding the adjacent side using
Pythagoras theorem :-
• Hypotenuse² = Base² + Height²
=> 40² = Base² + 15²
=> 1600 - 225 = Base²
=> Base² = 1375
=> Base = √1375
=> Base = 5√55
Now ,
- tan22° = Opposite/Adjacent = 15/5√55 = 3/√55
- sin22° = Opposite/hypotenuse = 15/40 = 5/4
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Given: It is given that the length of the painting is 24 inches and the width is 11 inches.
To find: Area of the mat
Solution:
The watercolor painting is 24 inches long by 11 inches wide.
So, the area of the painting is:
The length of painting with mat is = 24 in + 3 in + 3 in = 30 in
The width of painting with mat = 11 in + 3 in + 3 in = 17 in
Now to calculate the area of mat subtracts the area of painting from the area of the mat.
Hence, the area of the mat is 246 in².
Answer:
I believe they would have to sell 152 lollipops
Step-by-step explanation:
