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Vikki [24]
3 years ago
10

If the sun of a number is tripled, the result is nine less than twice the number. Find the number

Mathematics
1 answer:
Cloud [144]3 years ago
7 0
Attached the solution and work.

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PLEASE HELP URGENT!!! 30 POINTS TO WHOEVER ANSWERS BOTH QUESTIONS!!
Alex Ar [27]
This isn’t 30 points this is 15
3 0
3 years ago
a total of 582 tickets were sold for the school play. they were with adult tickets or student tickets. there were 68 fewer stude
topjm [15]

Answer:

257 adult tickets

Step-by-step explanation:

Let x be the total sold adult ticket.

Given:

Total 582 tickets were sold.

There were 68 fewer student tickets sold than adult tickets

Then there were x-68 students.

So, The total sold ticket equation is

x+(x-68)=582

2x-68=582

2x=582-68

x=\frac{514}{2}

x=257

Therefore, 257 adult tickets were sold

8 0
3 years ago
find the equation of a straight line passing through the point(4,5) and equally inclined to the lines 3x = 4y +7 and 5y= 12x +6
galina1969 [7]
<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:

y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5

The formula to be used in the proceeding steps is    a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting,      a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5)     =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope 

y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
3 0
3 years ago
In which quadrant of the coordinate graph does point F lie? Quadrant I Quadrant II Quadrant III Quadrant IV
Inga [223]

Answer:

it is c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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