Question

Marita spent $13.0 at the grocery store. She bought pears, kiwis and pineaples. Pears cost $0.50 each, pineapples cost $1.50 each, and kiwis are $0.30 each. how many of each kind of fruit did she buy if she bought 9 more pears than pineapples and 2 fewer kiwis than pears?

Answer 1

Answer:

There should be about 10 kiwis, 12 pears, and 3 pineapples.

Step-by-step explanation:

A problem on a search

Answer 2

Answer:

◘ 12 pears

◘ 3 pineapples

◘ 10 kiwis

Step-by-step explanation:

Let $x$ be the number of pears bought.

Therefore:

• number of pears = $x$

• number of pineapples = $x - 9$

• number of kiwis = $x - 2$

We know that the total cost was $13.50.

This means if she bought $x$ pears at $0.50 each, $(x - 9)$ pineapples at $1.50 each, and $(x -2)$ kiwis at $0.30 each, the total would be $13.50.

∴  $[x \times 0.50] + [(x-9) \times 1.5] + [(x-2) \times 0.3] = 13.50$

Expanding and multiplying:

⇒ $0.5 x + 1.5x - 13.5 + 0.3x - 0.6 = 13.5$

Collect like terms:

⇒ $2.3x -14.1 = 13.5$

Solve for $x$:

⇒ $2.3x = 13.5 + 14.1$

⇒ $2.3 x = 27.6$

⇒ $x = 27.6 \div 2.3$

⇒ $x = \bf 12$

Therefore, she bought:

• 12 pears

•  $x - 9$ = 12 - 9 = 3 pineapples

• $x - 2$ = 12 - 2 = 10 kiwis